[jquery] jQuery get the image src

I hope when I click the button, I can get the specific img src and show the img src in the div class img-block block.

HTML

<button class="button">Click</button>
<div class="img1">
    <img src="img.jpg" alt="">
</div>

<div class="img-block"></div>

CSS

.img-block{
    position: absolute;
    top:10%;
    right:10%;
    background-color: red;
    width: 500px;
    height: 500px;
}
.img1 img{
    width: 200px;
}

JS

$('.button').click(function(){
  var images = $('.img1 img').attr(src);
  alert(images);      
});

But now I face the problem is to get the img src.
So I use alert to make the test, the result is it alert nothing.

This is what you need

 $('img').context.currentSrc

In my case this format worked on latest version of jQuery:

$('img#post_image_preview').src;

When dealing with the HTML DOM (ie. this), the array selector [0] must be used to retrieve the jQuery element from the Javascript array.

$(this)[0].getAttribute('src');

You may find likr

$('.class').find('tag').attr('src');

for full url use

$('#imageContainerId').prop('src')

for relative image url use

$('#imageContainerId').attr('src')

function showImgUrl(){_x000D_
  console.log('for full image url ' + $('#imageId').prop('src') );_x000D_
  console.log('for relative image url ' + $('#imageId').attr('src'));_x000D_
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>_x000D_
<img id='imageId' src='images/image1.jpg' height='50px' width='50px'/>_x000D_
_x000D_
<input type='button' onclick='showImgUrl()' value='click to see the url of the img' />