If exists is there header file to include?
This code give compilation error:
#include <iostream>
using namespace std;
int main()
{
byte b = 2;
cout << b << endl;
return 0;
}
This question is related to
c++
if you are using windows, in WinDef.h you have:
typedef unsigned char BYTE;
There's also byte_lite, compatible with C++98, C++11 and later.
No, there is no type called "byte
" in C++. What you want instead is unsigned char
(or, if you need exactly 8 bits, uint8_t
from <cstdint>
, since C++11). Note that char
is not necessarily an accurate alternative, as it means signed char
on some compilers and unsigned char
on others.
namespace std
{
// define std::byte
enum class byte : unsigned char {};
};
This if your C++ version does not have std::byte will define a byte type in namespace std. Normally you don't want to add things to std, but in this case it is a standard thing that is missing.
std::byte from the STL does much more operations.
No, but since C++11 there is [u]int8_t.
Source: Stackoverflow.com