[docker] How can I use a local image as the base image with a dockerfile?

You can have - characters in your images. Assume you have a local image (not a local registry) named centos-base-image with tag 7.3.1611.

docker version 
      Client:
       Version:         1.12.6
       API version:     1.24
       Package version: docker-common-1.12.6-16.el7.centos.x86_64
       Go version:      go1.7.4

      Server:
       Version:         1.12.6
       API version:     1.24
       Package version: docker-common-1.12.6-16.el7.centos.x86_64
       Go version:      go1.7.4

docker images
 REPOSITORY            TAG
 centos-base-image     7.3.1611

Dockerfile

FROM centos-base-image:7.3.1611
RUN yum -y install epel-release libaio bc flex

Result

Sending build context to Docker daemon 315.9 MB
Step 1 : FROM centos-base-image:7.3.1611
  ---> c4d84e86782e
Step 2 : RUN yum -y install epel-release libaio bc flex
  ---> Running in 36d8abd0dad9
...

In the example above FROM is fetching your local image, you can provide additional instructions to fetch an image from your custom registry (e.g. FROM localhost:5000/my-image:with.tag). See https://docs.docker.com/engine/reference/commandline/pull/#pull-from-a-different-registry and https://docs.docker.com/registry/#tldr

Finally, if your image is not being resolved when providing a name, try adding a tag to the image when you create it

This GitHub thread describes a similar issue of not finding local images by name.

By omitting a specific tag, docker will look for an image tagged "latest", so either create an image with the :latest tag, or change your FROM