I want to get value from the database, in my case I use List to get the value from the database but I got this error
Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to id.co.bni.switcherservice.model.SwitcherServiceSource
at id.co.bni.switcherservice.controller.SwitcherServiceController.LoadData(SwitcherServiceController.java:48)
at id.co.bni.switcherservice.controller.SwitcherServiceController.main(SwitcherServiceController.java:62)
this is my code
Query LoadSource = session_source.createQuery("select CLIENT,SERVICE,SERVICE_TYPE,PROVIDER_CODE,COUNT(*) FROM SwitcherServiceSource" +
" where TIMESTAMP between :awal and :akhir" +
" and PROVIDER_CODE is not null group by CLIENT,SERVICE,SERVICE_TYPE,PROVIDER_CODE order by CLIENT,SERVICE,SERVICE_TYPE,PROVIDER_CODE");
LoadSource.setParameter("awal", fromDate);
LoadSource.setParameter("akhir", toDate);
List<SwitcherServiceSource> result_source = (List<SwitcherServiceSource>) LoadSource.list();
for(SwitcherServiceSource tes : result_source){
System.out.println(tes.getSERVICE());
}
any help will be pleasure :)
@raffian, did you mean like this??
List<Switcher> result = (List<Switcher>) LoadSource.list();
for(Switcher tes : result){
System.out.println(tes.getSERVICE());
}
java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to id.co.bni.switcherservice.model.SwitcherServiceSource
Problem is
(List<SwitcherServiceSource>) LoadSource.list();
This will return a List of Object arrays (Object[]) with scalar values for each column in the SwitcherServiceSource table. Hibernate will use ResultSetMetadata to deduce the actual order and types of the returned scalar values.
List<Object> result = (List<Object>) LoadSource.list();
Iterator itr = result.iterator();
while(itr.hasNext()){
Object[] obj = (Object[]) itr.next();
//now you have one array of Object for each row
String client = String.valueOf(obj[0]); // don't know the type of column CLIENT assuming String
Integer service = Integer.parseInt(String.valueOf(obj[1])); //SERVICE assumed as int
//same way for all obj[2], obj[3], obj[4]
}
In case entire entity is being return, better solution in spring JPA is use @Query(value = "from entity where Id in :ids")
This return entity type rather than object type
Your query execution will return list of Object[].
List result_source = LoadSource.list();
for(Object[] objA : result_source) {
// read it all
}
You need to add query.addEntity(SwitcherServiceSource.class) before calling the .list() on query.
I've faced such an issue and dig tones of material. So, to avoid ugly iteration you can simply tune your hql:
You need to frame your query like this
select entity from Entity as entity where ...
Also check such case, it perfectly works for me:
public List<User> findByRole(String role) {
Query query = sessionFactory.getCurrentSession().createQuery("select user from User user join user.userRoles where role_name=:role_name");
query.setString("role_name", role);
@SuppressWarnings("unchecked")
List<User> users = (List<User>) query.list();
return users;
}
So here we are extracting object from query, not a bunch of fields. Also it's looks much more pretty.
Source: Stackoverflow.com