If you must use a 2d array:
int numOfPairs = 10; String[][] array = new String[numOfPairs][2]; for(int i = 0; i < array.length; i++){ for(int j = 0; j < array[i].length; j++){ array[i] = new String[2]; array[i][0] = "original word"; array[i][1] = "rearranged word"; } }
Does this give you a hint?