How should I do integer division in Perl

Question

What is a good way to always do integer division in Perl   For example  I want   real   int   int  int   real   int  int   int   int

User · Answer

you can   use integer    it is explained by Michael Ratanapintha or else use manually    a 3 7   b 2 1    c int int  a  int  b      notice   int  is not casting  this is function for converting number to integer form  this is because Perl 5 does not have separate integer division  exception is when you  use integer   Then you will lose real division

User · Answer

int x  5  will round positive values toward the nearest integer  Rounding up is harder   To round toward zero   int  x   For the solutions below  include the following statement   use POSIX   To round down  POSIX  floor  x   To round up  POSIX  ceil  x   To round away from zero  POSIX  floor  x  - int  x    POSIX  ceil  x   To round off to the nearest integer  POSIX  floor  x  5   Note that int  x  5  fails badly for negative values  int -2 1  5  is int -1 6   which is -1

User · Answer

You can cast ints in Perl   int 5 1 5    3

User · Answer

The lexically scoped integer pragma forces Perl to use integer arithmetic in its scope   print 3 0 2 1     n          gt  1 42857142857143     use integer    print 3 0 2 1     n        gt  1   print 3 0 2 1     n          gt  1 42857142857143

User · Answer

Hope it works  int 9 4    2   Thanks Manojkumar

User · Answer

Integer division  x divided by  y       z   -1  amp   x    y  How does it work    x    y  return the floating point division   amp   perform a bit-wise AND  -1  stands for   amp HFFFFFFFF  for the largest integer     whence   z   -1  amp   x    y  gives the integer division

User · Answer

Eg 9   4   2 25  int 9    int 4    2  9   4 - remainder   deniminator   2  9  4 - 9   4   4   2

[perl] How should I do integer division in Perl?

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