Remove end of line characters from Java string

Question

I have string like this   hello java book    I want remove  r and  n from String hello r njava r nbook   I want the result to be  hellojavabook   How can I do this

User · Answer

Have you tried using the replaceAll method to replace any occurence of  n or  r with the empty String

User · Answer

Regex with replaceAll   public class Main       public static void main final String   argv                 String str           str    hello r njava r nbook           str   str replaceAll     r   n                 System out println str             If you only want to remove  r n when they are pairs  the above code removes either  r or  n  do this instead   str   str replaceAll    r  n

User · Answer

You can either directly pass line terminator e g   n  if you know the line terminator in Windows  Mac or UNIX  Alternatively you can use following code to replace line breaks in either of three major operating system   str   str replaceAll    r  n   r   n           Above code line will replace line breaks with space in Mac  Windows and Linux  Also you can use line-separator  It will work for all OS  Below is the code snippet for line-separator   String lineSeparator System lineSeparator    String newString yourString replace lineSeparator

User · Answer

Did you try  string trim       This is meant to trim all leading and leaning while spaces in the string  Hope this helps   Edit   I was not explicit enough   So  when you string split    you will have a string   - for each of the strings in the array  do a string trim   and then append it   String   tokens   yourString split       StringBuffer buff   new StringBuffer    for  String token   tokens      buff append token trim         Use stringBuffer Builder instead of appending in the same string

User · Answer

static byte   discardWhitespace byte   data        byte groomedData     new byte data length       int bytesCopied   0       for  int i   0  i  lt  data length  i              switch  data i                 case  byte    n                case  byte    r                    break              default                  groomedData bytesCopied      data i                        byte packedData     new byte bytesCopied        System arraycopy groomedData  0  packedData  0  bytesCopied        return packedData      Code found on commons-codec project

User · Answer

public static void main final String   argv         String str       str    hello r n tjava r nbook       str   str replaceAll     r   n   t             System out println str       It would be useful to add the tabulation in regex too

User · Answer

If you want to avoid the regex  or must target an earlier JVM  String replace   will do   str str replace   r      replace   n         And to remove a CRLF pair   str str replace   r n         The latter is more efficient than building a regex to do the same thing   But I think the former will be faster as a regex since the string is only parsed once

User · Answer

You can use unescapeJava from org apache commons text StringEscapeUtils like below   str    hello r njava r nbook   StringEscapeUtils unescapeJava str

User · Answer

Given a String str   str   str replaceAll      r      str   str replaceAll      n

User · Answer

Hey we can also use this regex solution   String chomp   StringUtils normalizeSpace sentence replaceAll     r  n

[java] Remove end of line characters from Java string

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