[java] Java: how to initialize String[]?

Error

% javac  StringTest.java 
StringTest.java:4: variable errorSoon might not have been initialized
        errorSoon[0] = "Error, why?";

Code

public class StringTest {
        public static void main(String[] args) {
                String[] errorSoon;
                errorSoon[0] = "Error, why?";
        }
}

String[] errorSoon = { "foo", "bar" };

-- or --

String[] errorSoon = new String[2];
errorSoon[0] = "foo";
errorSoon[1] = "bar";

I believe you just migrated from C++, Well in java you have to initialize a data type(other then primitive types and String is not a considered as a primitive type in java ) to use them as according to their specifications if you don't then its just like an empty reference variable (much like a pointer in the context of C++).

public class StringTest {
    public static void main(String[] args) {
        String[] errorSoon = new String[100];
        errorSoon[0] = "Error, why?";
        //another approach would be direct initialization
        String[] errorsoon = {"Error , why?"};   
    }
}

In Java 8 we can also make use of streams e.g.

String[] strings = Stream.of("First", "Second", "Third").toArray(String[]::new);

In case we already have a list of strings (stringList) then we can collect into string array as:

String[] strings = stringList.stream().toArray(String[]::new);

You can use below code to initialize size and set empty value to array of Strings

String[] row = new String[size];
Arrays.fill(row, "");

String[] string=new String[60];
System.out.println(string.length);

it is initialization and getting the STRING LENGTH code in very simple way for beginners

String[] errorSoon = new String[n];

With n being how many strings it needs to hold.

You can do that in the declaration, or do it without the String[] later on, so long as it's before you try use them.

String[] args = new String[]{"firstarg", "secondarg", "thirdarg"};

String Declaration:

String str;

String Initialization

String[] str=new String[3];//if we give string[2] will get Exception insted
str[0]="Tej";
str[1]="Good";
str[2]="Girl";

String str="SSN"; 

We can get individual character in String:

char chr=str.charAt(0);`//output will be S`

If I want to to get individual character Ascii value like this:

System.out.println((int)chr); //output:83

Now i want to convert Ascii value into Charecter/Symbol.

int n=(int)chr;
System.out.println((char)n);//output:S

You can always write it like this

String[] errorSoon = {"Hello","World"};

For (int x=0;x<errorSoon.length;x++) // in this way u create a for     loop that would like display the elements which are inside the array     errorSoon.oh errorSoon.length is the same as errorSoon<2 

{
   System.out.println(" "+errorSoon[x]); // this will output those two     words, at the top hello and world at the bottom of hello.  
}

String[] arr = {"foo", "bar"};

If you pass a string array to a method, do:

myFunc(arr);

or do:

myFunc(new String[] {"foo", "bar"});