[sql-server-2008] how to show only even or odd rows in sql server 2008?

i have a table MEN in sql server 2008 that contain 150 rows.

how i can show only the even or only the odd rows ?

thank's in advance

Assuming your table has auto-numbered field "RowID" and you want to select only records where RowID is even or odd.

To show odd:

Select * from MEN where (RowID % 2) = 1

To show even:

Select * from MEN where (RowID % 2) = 0

odd number query:

SELECT *
  FROM   ( SELECT rownum rn, empno, ename
           FROM emp
         ) temp
  WHERE  MOD(temp.rn,2) = 1

even number query:

SELECT *
  FROM   ( SELECT rownum rn, empno, ename
           FROM emp
         ) temp
  WHERE  MOD(temp.rn,3) = 0

FASTER: Bitwise instead of modulus.

select * from MEN where (id&1)=0;

Random question: Do you actually use uppercase table names? Usually uppercase is reserved for keywords. (By convention)

To fetch even records

select *
from (select id,row_number() over (order by id) as r from table_name) T
where mod(r,2)=0;

To fetch odd records

select *
from (select id,row_number() over (order by id) as r from table_name) T
where mod(r,2)=1;

To select an odd id from a table:

select * from Table_Name where id%2=1;

To select an even id from a table:

select * from Table_Name where id%2=0;

for SQL > odd:

select * from id in(select id from employee where id%2=1)

for SQL > Even:

select * from id in(select id from employee where id%2=0).....f5

Oracle Database

ODD ROWS

select * from (select mod(rownum,2) as num , employees.* from employees) where num =0;

EVEN ROWS

select * from (select mod(rownum,2) as num , employees.* from employees) where num =1; 

Following is for fetching even number:: Select * from MEN where Men_ID%2=0;

Following is for fetching odd number:: Select * from MEN where Men_ID%2!=0;

Here MEN is your table_name Men_ID is the column in MEN Table.

SELECT *
  FROM   
  ( 
     SELECT rownum rn, empno, ename
     FROM emp
  ) temp
  WHERE  MOD(temp.rn,2) = 1

Try following

SELECT * FROM Worker WHERE MOD (WORKER_ID, 2) <> 0;

  SELECT * FROM (SELECT ROW_NUMBER () OVER (ORDER BY sal DESC) row_number, sr,sal FROM empsal) a WHERE (row_number%2) = 1

and

      SELECT * FROM (SELECT ROW_NUMBER () OVER (ORDER BY sal DESC) row_number, sr,sal FROM   empsal) a WHERE (row_number%2) = 0

select * from Tablename 
where id%2=0

Check out ROW_NUMBER()

SELECT t.First, t.Last
FROM (
    SELECT *, Row_Number() OVER(ORDER BY First, Last) AS RowNumber 
            --Row_Number() starts with 1
    FROM Table1
) t
WHERE t.RowNumber % 2 = 0 --Even
--WHERE t.RowNumber % 2 = 1 --Odd

For even values record :

select * from www where mod(salary,2)=0;

For odd values record:

select * from www where mod(salary,2)!=0;

Try this :

odd :

select * from( 
SELECT col1, col2, ROW_NUMBER() OVER(ORDER BY col1 DESC) AS 'RowNumber', 
FROM table1
) d where (RowNumber % 2) = 1 

even :

select * from( 
SELECT col1, col2, ROW_NUMBER() OVER(ORDER BY col1 DESC) AS 'RowNumber', 
FROM table1
) d where (RowNumber % 2) = 0

Here’s a simple and straightforward answer to your question, (I think). I am using the TSQL2012 sample database and I am returning only even or odd rows based on “employeeID” in the “HR.Employees” table.

USE TSQL2012;
GO

Return only Even numbers of the employeeID:

SELECT *
FROM HR.Employees
WHERE (empid % 2) = 0;
GO

Return only Odd numbers of the employeeID:

SELECT *
FROM HR.Employees
WHERE (empid % 2) = 1;
GO

Hopefully, that’s the answer you were looking for.