How to get the last characters in a String in Java regardless of String size

Question

I m looking for a way to pull the last characters from a String  regardless of size  Lets take these strings into example    abcd  efg  1006746   bhddy  nshhf36  1006754   hfquv  nd  5894254    As you can see  completely random strings  but they have 7 numbers at the end  How would I be able to take those 7 numbers   Edit   I just realized that String   string   s split        would work great here  as long as I call string 2  for the numbers and string 1  for anything in the middle

User · Answer

You can achieve it using this single line code :

String numbers = text.substring(text.length() - 7, text.length());

But be sure to catch Exception if the input string length is less than 7.

You can replace 7 with any number say N, if you want to get last 'N' characters.

User · Answer

org apache commons lang3 StringUtils substring s  -7     gives you the answer  It returns the input if it is shorter than 7  and null if s    null  It never throws an exception   See https   commons apache org proper commons-lang apidocs org apache commons lang3 StringUtils html substring-java lang String-int-int-

User · Answer

E g    abcd  efg  1006746   bhddy  nshhf36  1006754   hfquv  nd  5894254   -Step 1  String firstString     abcd  efg  1006746    -Step 2  String lastSevenNumber   firstString substring firstString lastIndexOf       firstString length    trim

User · Answer

This code works for me perfectly   String numbers   text substring Math max 0  text length   - 7

User · Answer

This should work   Integer i  Integer parseInt text substring text length   - 7

User · Answer

This question is the top Google result for  Java String Right    Surprisingly  no-one has yet mentioned Apache Commons StringUtils right     String numbers   org apache commons lang StringUtils right  text  7      This also handles the case where text is null  where many of the other answers would throw a NullPointerException

User · Answer

I d use either String split or a regex     Using String split  String   numberSplit   yourString split         String numbers   numberSplit   numberSplit length-1           last array element     Using RegEx  requires import java util regex     String numbers        Matcher numberMatcher   Pattern compile   0-9  7    matcher yourString        if  matcher find                   numbers   matcher group 0

User · Answer

String inputstr    abcd  efg  1006746  int startindex   inputstr length   - 10  String outputtendigitstr   inputstr substring startindex     Make sure you check string length is more than 10

User · Answer

Lots of things you could do   s substring s lastIndexOf        1     will get everything after the last colon   s substring s lastIndexOf        1     everything after the last space   String numbers     s split    0-9        splits off all sequences of digits  the last element of the numbers array is probably what you want

User · Answer

How about   String numbers   text substring text length   - 7     That assumes that there are 7 characters at the end  of course  It will throw an exception if you pass it  12345   You could address that this way   String numbers   text substring Math max 0  text length   - 7      or  String numbers   text length    lt   7   text   text substring text length   - 7     Note that this still isn t doing any validation that the resulting string contains numbers - and it will still throw an exception if text is null

User · Answer

StringUtils substringAfterLast  abcd  efg  1006746              1006746    As long as the format of the string is fixed you can use substringAfterLast

[java] How to get the last characters in a String in Java, regardless of String size

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