Say we have the following data frame:
> df
A B C
1 1 2 3
2 4 5 6
3 7 8 9
We can select column 'B' from its index:
> df[,2]
[1] 2 5 8
Is there a way to get the index (2) from the column label ('B')?
This question is related to
r
Here is an answer that will generalize Henrik's answer.
df=data.frame(A=rnorm(100), B=rnorm(100), C=rnorm(100))
numeric_columns<-c('A', 'B', 'C')
numeric_index<-sapply(1:length(numeric_columns), function(i)
grep(numeric_columns[i], colnames(df)))
The following will do it:
which(colnames(df)=="B")
Use t
function:
t(colnames(df))
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] "var1" "var2" "var3" "var4" "var5" "var6"
I wanted to see all the indices for the colnames because I needed to do a complicated column rearrangement, so I printed the colnames as a dataframe. The rownames are the indices.
as.data.frame(colnames(df))
1 A
2 B
3 C
Following on from chimeric's answer above:
To get ALL the column indices in the df, so i used:
which(!names(df)%in%c())
or store in a list:
indexLst<-which(!names(df)%in%c())
This seems to be an efficient way to list vars with column number:
cbind(names(df))
Output:
[,1]
[1,] "A"
[2,] "B"
[3,] "C"
Sometimes I like to copy variables with position into my code so I use this function:
varnums<- function(x) {w=as.data.frame(c(1:length(colnames(x))),
paste0('# ',colnames(x)))
names(w)= c("# Var/Pos")
w}
varnums(df)
Output:
# Var/Pos
# A 1
# B 2
# C 3
match("B", names(df))
Can work also if you have a vector of names.
Source: Stackoverflow.com