Comparing strings by their alphabetical order

Question

String s1    Project   String s2    Sunject     I want to compare the two above string by their alphabetic order  which in this case  Project  then  Sunject  as  P  comes before  S    Does anyone know how to do that in Java

User · Answer

Take a look at the String compareTo method   s1 compareTo s2    From the javadocs      The result is a negative integer if   this String object lexicographically   precedes the argument string  The   result is a positive integer if this   String object lexicographically   follows the argument string  The   result is zero if the strings are   equal  compareTo returns 0 exactly   when the equals Object  method would   return true

User · Answer

import java io    import java util    public class CandidateCode       public static void main String args     throws Exception          Scanner sc   new Scanner System in              int n  Integer parseInt sc nextLine                String arr     new String n           for  int i   0  i  lt  arr length  i                      arr i    sc nextLine                                 for int i   0  i  lt arr length    i                for  int j   i   1  j  lt arr length    j                    if  arr i  compareTo arr j    gt  0                        String temp   arr i                       arr i    arr j                       arr j    temp                                                    for int i   0  i  lt arr length  i                  System out println arr i

User · Answer

As others suggested  you can use String compareTo String    But if you are sorting a list of Strings and you need a Comparator  you don t have to implement it  you can use Comparator naturalOrder   or Comparator reverseOrder

User · Answer

For alphabetical order following nationalization  use Collator     Get the Collator for US English and set its strength to PRIMARY Collator usCollator   Collator getInstance Locale US   usCollator setStrength Collator PRIMARY   if  usCollator compare  abc    ABC      0         System out println  Strings are equivalent        For a list of supported locales  see JDK 8 and JRE 8 Supported Locales

User · Answer

String compareTo might or might not be what you need   Take a look at this link if you need localized ordering of strings

User · Answer

String a           String b             int compare   a compareTo b      if  compare  lt  0            a is smaller   else if  compare  gt  0          a is larger    else           a is equal to b

User · Answer

You can call either string s compareTo method  java lang String compareTo   This feature is well documented on the java documentation site   Here is a short program that demonstrates it   class StringCompareExample       public static void main String args             String s1    Project   String s2    Sunject           verboseCompare s1  s2           verboseCompare s2  s1           verboseCompare s1  s1              public static void verboseCompare String s1  String s2           System out println  Comparing       s1       to       s2                      int comparisonResult   s1 compareTo s2           System out println  The result of the comparison was     comparisonResult            System out print  This means that       s1                   if comparisonResult  lt  0               System out println  lexicographically precedes       s2                    else if comparisonResult  gt  0               System out println  lexicographically follows       s2                    else              System out println  equals       s2                             System out println              Here is a live demonstration that shows it works  http   ideone com Drikp3

[java] Comparing strings by their alphabetical order

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