How to remove the last character from a string

Question

I want to remove the last character from a string  I ve tried doing this   public String method String str        if  str charAt str length  -1    x            str   str replace str substring str length  -1                return str        else          return str            Getting the length of the string - 1 and replacing the last letter with nothing  deleting it   but every time I run the program  it deletes middle letters that are the same as the last letter   For example  the word is  admirer   after I run the method  I get  admie   I want it to return the word admire

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In Kotlin you can used dropLast   method of the string class  It will drop the given number from string  return a new string  var string1    Some Text  string1   string1 dropLast 1

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removes last occurence of the  xxx        System out println  aaa xxx aaa xxx   replaceAll  xxx   xxx         1       removes last occurrence of the  xxx  if it is last       System out println  aaa xxx aaa    replaceAll  xxx  s             you can replace the  xxx  on what you want but watch out on special chars

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Why not just one liner  public static String removeLastChar String str        return removeLastChars str  1      public static String removeLastChars String str  int chars        return str substring 0  str length   - chars      Full Code public class Main       public static void main  String   args  throws java lang Exception           String s1    quot Remove Last CharacterY quot           String s2    quot Remove Last Character2 quot           System out println  quot After removing s1   quot    removeLastChar s1     quot    quot            System out println  quot After removing s2   quot    removeLastChar s2     quot    quot                   public static String removeLastChar String str            return removeLastChars str  1              public static String removeLastChars String str  int chars            return str substring 0  str length   - chars            Demo

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How can a simple task be made complicated  My solution is  public String removeLastChar String s        return s 0  -1     or public String removeLastChar String s        if  s length    gt  0            return s 0  -1            return s

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Don t try to reinvent the wheel  while others have already written libraries to perform string manipulation   org apache commons lang3 StringUtils chop

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public String removeLastChar String s        if   Util isEmpty s             s   s substring 0  s length  -1             return s

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For kotlin check out      val string     lt  lt  lt First Grade gt  gt  gt       println string drop 6      st Grade gt  gt  gt      println string dropLast 6       lt  lt  lt First Gr     println string dropWhile    it isLetter         First Grade gt  gt  gt      println string dropLastWhile    it isLetter          lt  lt  lt First Grade

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Suppose total length of my string 24 I want to cut last character after position 14 to end  mean I want starting 14 to be there  So I apply following solution   String date    2019-07-31T22 00 00 000Z   String result   date substring 0  date length   - 14

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Most answers here forgot about surrogate pairs   For instance  the character   codepoint U 1D56B  does not fit into a single char  so in order to be represented  it must form a surrogate pair of two chars   If one simply applies the currently accepted answer  using str substring 0  str length   - 1   one splices the surrogate pair  leading to unexpected results   One should also include a check whether the last character is a surrogate pair   public static String removeLastChar String str        Objects requireNonNull str   The string should not be null        if  str isEmpty              return str             char lastChar   str charAt str length   - 1       int cut   Character isSurrogate lastChar    2   1      return str substring 0  str length   - cut

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I had to write code for a similar problem  One way that I was able to solve it used a recursive method of coding   static String removeChar String word  char charToRemove        for int i   0  i  lt  word lenght    i                  if word charAt i     charToRemove                        String newWord   word substring 0  i    word substring i   1               return removeChar newWord  charToRemove                        return word      Most of the code I ve seen on this topic doesn t use recursion so hopefully I can help you or someone who has the same problem

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Use this    if string endsWith  x           string  string substring 0  string length   - 1

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Java 8     import java util Optional   public class Test     public static void main String   args  throws InterruptedException         System out println removeLastChar  test-abc            public static String removeLastChar String s        return Optional ofNullable s         filter str - gt  str length      0         map str - gt  str substring 0  str length   - 1          orElse s             Output   test-ab

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if you have special character like   in json just use String replace          otherwise you must rewrite all character in string minus the last

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creating StringBuilder  StringBuilder builder   new StringBuilder requestString       removing last character from String  builder deleteCharAt requestString length   - 1

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Remove n last characters      System out println removeLast  Hello   333  3     public String removeLast String mes  int n        return mes    null  amp  amp   mes isEmpty    amp  amp  mes length   gt n            mes substring 0  mes length  -n   mes        Leave substring before character string      System out println leaveBeforeChar  Hello   123    1      public String leaveBeforeChar String mes  String last        return mes    null  amp  amp   mes isEmpty    amp  amp  mes lastIndexOf last   -1            mes substring 0  mes lastIndexOf last    mes

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u can do i hereString    hereString replace hereString chatAt hereString length   - 1     whitespeace

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A one-liner answer  just a funny alternative - do not try this at home  and great answers already given    public String removeLastChar String s  return  s    null  amp  amp  s length      0    s substring 0  s length   - 1   s

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If you want to remove specific character at the end you could use  myString removeSuffix  quot x quot

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This is the one way to remove the last character in the string   Scanner in   new Scanner System in   String s   in nextLine    char array     s toCharArray    int l   array length  for  int i   0  i  lt  l-1  i          System out print array i

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public String removeLastCharacter String str          String result   null          if   str    null   amp  amp   str length    gt  0               return str substring 0  str length   - 1                     else              return

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just replace the condition of  if  like this    if a substring a length  -1  equals  x       this will do the trick for you

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Look to StringBuilder Class        StringBuilder sb new StringBuilder  toto         System out println sb deleteCharAt sb length  -1     display  toto

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if  str endsWith  quot x quot        return str substring 0  str length   - 1     return str     For example  the word is  quot admirer quot   after I run the method  I get  quot admie  quot  I want it to return the word admire   In case you re trying to stem English words  Stemming is the process for reducing inflected  or sometimes derived  words to their stem  base or root form   generally a written word form      A stemmer for English  for example  should identify the string  quot cats quot   and possibly  quot catlike quot    quot catty quot  etc   as based on the root  quot cat quot   and  quot stemmer quot    quot stemming quot    quot stemmed quot  as based on  quot stem quot   A stemming algorithm reduces the words  quot fishing quot    quot fished quot    quot fish quot   and  quot fisher quot  to the root word   quot fish quot    Difference between Lucene stemmers  EnglishStemmer  PorterStemmer  LovinsStemmer outlines some Java options

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How to make the char in the recursion at the end   public static String  removeChar String word  char charToRemove                String char toremove Character toString charToRemove           for int i   0  i  lt  word length    i                          if word charAt i     charToRemove                                String newWord   word substring 0  i    word substring i   1                   return removeChar newWord charToRemove                                   System out println word           return word          for exemple   removeChar   hello world  let s go    l      heo word  et s go llll  removeChar  you should not go   o      yu shuld nt goooo

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Here s an answer that works with codepoints outside of the Basic Multilingual Plane  Java 8     Using streams   public String method String str        return str codePoints                limit str codePoints   count   - 1               mapToObj i- gt new String Character toChars i                 collect Collectors joining         More efficient maybe   public String method String str        return str isEmpty        str substring 0  str length   - Character charCount str codePointBefore str length

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string   string substring 0   string length   - 1     I m using this in my code  it s easy and simple  it only works while the String is  gt  0  I have it connected to a button and inside the following if statement if  string length    gt  0        string   string substring 0   string length   - 1

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As far as the readability is concerned  I find this to be the most concise  StringUtils substring  string   0  -1     The negative indexes can be used in Apache s StringUtils utility  All negative numbers are treated from offset from the end of the string

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replace will replace all instances of a letter  All you need to do is use substring     public String method String str        if  str    null  amp  amp  str length    gt  0  amp  amp  str charAt str length   - 1      x             str   str substring 0  str length   - 1             return str

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Since we re on a subject  one can use regular expressions too   aaabcd  replaceFirst               gt  aaabc

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public String removeLastChar String s        if  s    null    s length      0            return s            return s substring 0  s length  -1

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Why not use the escape sequence        System out println str     b      Life is much easier now   XD     A readable one-liner

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The described problem and proposed solutions sometimes relate to removing separators  If this is your case  then have a look at Apache Commons StringUtils  it has a method called removeEnd which is very elegant   Example   StringUtils removeEnd  string 1 string 2 string 3            Would result in   string 1 string 2 string 3

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Easy Peasy   StringBuilder sb  new StringBuilder    for Entry lt String String gt  entry   map entrySet              sb append entry getKey           entry getValue             String requiredString   sb substring 0  sb length   - 1

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We can use substring  Here s the example   public class RemoveStringChar        public static void main String   args                    String strGiven    Java           System out println  Before removing string character -     strGiven           System out println  After removing string character -     removeCharacter strGiven  3               public static String removeCharacter String strRemove  int position                   return strRemove substring 0  position    strRemove substring position   1

[java] How to remove the last character from a string?

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