Consider this line of code:
Math.abs(firstDouble - secondDouble) < Double.MIN_NORMAL
It returns whether firstDouble is equal to secondDouble. I'm unsure as to whether or not this would work in your exact case (as Kevin pointed out, performing any math on floating points can lead to imprecise results) however I was having difficulties with comparing two double which were, indeed, equal, and yet using the 'compareTo' method didn't return 0.
I'm just leaving this there in case anyone needs to compare to check if they are indeed equal, and not just similar.