Here is my code snippet:
public void joinRoom(String room) throws MulticasterJoinException {
String statusCheck = this.transmit("room", "join", room + "," + this.groupMax + "," + this.uniqueID);
if (statusCheck != "success") {
throw new MulticasterJoinException(statusCheck, this.PAppletRef);
}
}
However for some reason, if (statusCheck != "success")
is returning false
, and thereby throwing the MulticasterJoinException
.
This question is related to
java
==
and !=
work on object identity. While the two String
s have the same value, they are actually two different objects.
use !"success".equals(statusCheck)
instead.
You need to use the method equals()
when comparing a string, otherwise you're just comparing the object references to each other, so in your case you want:
if (!statusCheck.equals("success")) {
you can use equals() method to statisfy your demands. == in java programming language has a different meaning!
do the one of these.
if(!statusCheck.equals("success"))
{
//do something
}
or
if(!"success".equals(statusCheck))
{
//do something
}
Sure, you can use equals
if you want to go along with the crowd, but if you really want to amaze your fellow programmers check for inequality like this:
if ("success" != statusCheck.intern())
intern method is part of standard Java String API.
Please use !statusCheck.equals("success")
instead of !=
.
Here are more details.
Source: Stackoverflow.com