How to remove first and last character of a string

Question

I have worked in SOAP message to get LoginToken from Webservice  and store the LoginToken in String and used System out println LoginToken   to print  This prints  wdsd34svdf   but I want only wdsd34svdf so  how to remove square bracket  please any one help me   Thanks  Example   String LoginToken getName   toString    System out println  LoginToken    LoginToken     Output   wdsd34svdf  I want wdsd34svdf

User · Answer

Try this to remove the first and last bracket of string ex  1 2 3  String s  str replaceAll  quot   quot    quot  quot   replaceAll  quot   quot    quot  quot     Exptected result   1 2 3

User · Answer

This is generic solution   str replaceAll

User · Answer

You can always use substring   String loginToken   getName   toString    loginToken   loginToken substring 1  loginToken length   - 1

User · Answer

SOLUTION 1  def spaceMeOut str1      print str1 1 len str1 -1    str1  Hello  print spaceMeOut str1    SOLUTION 2  def spaceMeOut str1     res str1 1 len str1 -1     print      format res    str1  Hello  print spaceMeOut str1

User · Answer

This way you can remove 1 leading     and 1 trailing     character  If your string happen to not start with     or end with     it won t remove anything   str replaceAll

User · Answer

It s easy  You need to find index of   and    then substring   Here   is always at start and   is at end    String loginToken    quot  wdsd34svdf  quot   System out println  loginToken substring  1  loginToken length   - 1

User · Answer

StringUtils s removeStart and removeEnd method help to remove string from start and end of a string   In this case we could also use combination of this two method  String string     wdsd34svdf    System out println StringUtils removeStart StringUtils removeEnd string

User · Answer

This will gives you basic idea      String str         String str1         Scanner S new Scanner System in       System out println  Enter the string        str S nextLine        int length str length        for int i 0 i lt length i                  str1 str substring 1  length-1             System out println str1

User · Answer

I had a similar scenario  and I thought that something like   str replaceAll                 looked cleaner  Of course  if your token might have brackets in it  that wouldn t work

User · Answer

this is perfectly working fine  String str     wdsd34svdf      String str1   str replace         replace           String str1   str replaceAll    a-zA-Z0-9         System out println str1     String strr     wdsd 340  svdf    String strr1   str replaceAll    a-zA-Z0-9         System out println strr1

User · Answer

Another solution for this issue is use commons-lang  since version 2 0  StringUtils substringBetween String str  String open  String close  method  Main advantage is that it s null safe operation   StringUtils substringBetween   wdsd34svdf                  returns wdsd34svdf

User · Answer

In Kotlin  private fun removeLastChar str  String    String        return if  str    null    str isEmpty    str else str substring 0  str length - 1

[java] How to remove first and last character of a string?

Examples related to java

Examples related to string