[java] Get size of an Iterable in Java

I need to figure out the number of elements in an Iterable in Java. I know I can do this:

Iterable values = ...
it = values.iterator();
while (it.hasNext()) {
  it.next();
  sum++;
}

I could also do something like this, because I do not need the objects in the Iterable any further:

it = values.iterator();
while (it.hasNext()) {
  it.remove();
  sum++;
}

A small scale benchmark did not show much performance difference, any comments or other ideas for this problem?

This question is related to java iterable

The answer is


This is perhaps a bit late, but may help someone. I come across similar issue with Iterable in my codebase and solution was to use for each without explicitly calling values.iterator();.

int size = 0;
for(T value : values) {
   size++;
}

Why don't you simply use the size() method on your Collection to get the number of elements?

Iterator is just meant to iterate,nothing else.


You can cast your iterable to a list then use .size() on it.

Lists.newArrayList(iterable).size();

For the sake of clarity, the above method will require the following import:

import com.google.common.collect.Lists;

I would go for it.next() for the simple reason that next() is guaranteed to be implemented, while remove() is an optional operation.

E next()

Returns the next element in the iteration.

void remove()

Removes from the underlying collection the last element returned by the iterator (optional operation).


Instead of using loops and counting each element or using and third party library we can simply typecast the iterable in ArrayList and get its size.

((ArrayList) iterable).size();

java 8 and above

StreamSupport.stream(data.spliterator(), false).count();

Strictly speaking, Iterable does not have size. Think data structure like a cycle.

And think about following Iterable instance, No size:

    new Iterable(){

        @Override public Iterator iterator() {
            return new Iterator(){

                @Override
                public boolean hasNext() {
                    return isExternalSystemAvailble();
                }

                @Override
                public Object next() {
                    return fetchDataFromExternalSystem();
                }};
        }};

As for me, these are just different methods. The first one leaves the object you're iterating on unchanged, while the seconds leaves it empty. The question is what do you want to do. The complexity of removing is based on implementation of your iterable object. If you're using Collections - just obtain the size like was proposed by Kazekage Gaara - its usually the best approach performance wise.


If you are working with java 8 you may use:

Iterable values = ...
long size = values.spliterator().getExactSizeIfKnown();

it will only work if the iterable source has a determined size. Most Spliterators for Collections will, but you may have issues if it comes from a HashSetor ResultSetfor instance.

You can check the javadoc here.

If Java 8 is not an option, or if you don't know where the iterable comes from, you can use the same approach as guava:

  if (iterable instanceof Collection) {
        return ((Collection<?>) iterable).size();
    } else {
        int count = 0;
        Iterator iterator = iterable.iterator();
        while(iterator.hasNext()) {
            iterator.next();
            count++;
        }
        return count;
    }