Specifically how do I tell spring-data-jpa that users that have the same username and firstname are actually EQUAL and that it is supposed to update the entity. Overriding equals did not work.
For this particular purpose one can introduce a composite key like this:
CREATE TABLE IF NOT EXISTS `test`.`user` (
`username` VARCHAR(45) NOT NULL,
`firstname` VARCHAR(45) NOT NULL,
`description` VARCHAR(45) NOT NULL,
PRIMARY KEY (`username`, `firstname`))
Mapping:
@Embeddable
public class UserKey implements Serializable {
protected String username;
protected String firstname;
public UserKey() {}
public UserKey(String username, String firstname) {
this.username = username;
this.firstname = firstname;
}
// equals, hashCode
}
Here is how to use it:
@Entity
public class UserEntity implements Serializable {
@EmbeddedId
private UserKey primaryKey;
private String description;
//...
}
JpaRepository would look like this:
public interface UserEntityRepository extends JpaRepository<UserEntity, UserKey>
Then, you could use the following idiom: accept DTO with user info, extract name and firstname and create UserKey, then create a UserEntity with this composite key and then invoke Spring Data save() which should sort everything out for you.