The code:
a <- structure(list(`X$Days` = c("10", "38", "66", "101", "129", "185", "283",
"374")), .Names = "X$Days")
Then a
is like
$`X$Days`
[1] "10" "38" "66" "101" "129" "185" "283" "374"
I would like to coerce a
to an array of numeric values, but coercing functions return me
Error: (list) object cannot be coerced to type 'double'
Thanks,
This question is related to
r
You can also use list subsetting to select the element you want to convert. It would be useful if your list had more than 1 element.
as.numeric(a[[1]])
If your list as multiple elements that need to be converted to numeric, you can achieve this with lapply(a, as.numeric)
.
In this case a loop will also do the job (and is usually sufficiently fast).
a <- array(0, dim=dim(X))
for (i in 1:ncol(X)) {a[,i] <- X[,i]}
There are problems with some data. Consider:
as.double(as.character("2.e")) # This results in 2
Another solution:
get_numbers <- function(X) {
X[toupper(X) != tolower(X)] <- NA
return(as.double(as.character(X)))
}
Source: Stackoverflow.com