Ascending and Descending Number Order in java

Question

I m doing an ascending and descending order number in java and here s my code   System out print  Enter How Many Inputs      int num1   Integer parseInt in readLine     int arr     new int num1    for  int i   0  i lt num1  i          System out print  Enter Value       i   1              arr i   Integer parseInt in readLine        System out print  Numbers in Ascending Order       for int i   0  i  lt  arr length  i          Arrays sort arr       System out print       arr i       System out println       System out print  Numbers in Descending Order         Currently  the code generates the following   Enter How Many Inputs  5 Enter Value  1 3 Enter Value  2 5 Enter Value  3 6 Enter Value  4 11 Enter Value  5 2 Numbers in Ascending Order  2 3 5 6 11  Numbers in Descending Order     So  the Arrays sort arr  call seems to work - but I m looking for a similarly simple way to provide the descending sort  and can t find it in the documentation  Any ideas

User · Answer

use reverse for loop to print in descending order   for  int i   ar length - 1  i  gt   0  i--        Arrays sort ar       System out println ar i

User · Answer

int arr       12  13  54  16  25  8  78     for  int i   0  i  lt  arr length  i          Arrays sort arr       System out println arr i

User · Answer

you can make two function one for Ascending and another for Descending the next two functions work after convert array to List   public List lt Integer gt  sortDescending List lt Integer gt  arr       Comparator lt Integer gt  c   Collections reverseOrder        Collections sort arr c       return arr        next function   public List lt Integer gt  sortAscending List lt Integer gt  arr          Collections sort arr       return arr

User · Answer

Just sort the array in ascending order and print it backwards   Arrays sort arr   for int i   arr length-1  i  gt   0   i--          print arr i

User · Answer

Sort the array just as before  but print the elements out in reverse order  using a loop that counts down rather than counting up   Also  move the sort out of the loop - you are currently sorting the array over and over again when you only need to sort it once                   Arrays sort arr                   for int i   0  i  lt  arr length  i                           Arrays sort arr      not here                     System out print       arr i                                      for int i   arr length-1  i  gt   0  i--                         Arrays sort arr      not here                     System out print       arr i

User · Answer

Why are you using array and bothering with the first question of number of wanted numbers    Prefer an ArrayList associated with a corresponding comparator   List numbers   new Arraylist      add read numbers  int  with autoboxing if jdk gt  5  or Integer directly  into it    Initialize the associated comparator reversing order   since Integer implements Comparable  Comparator comparator   Collections reverseOrder       Sort the list Collections sort numbers comparator

User · Answer

You can sort the array first  and then loop through it twice  once in both directions   Arrays sort arr    System out print  Numbers in Ascending Order       for int i   0  i  lt  arr length  i        System out print        arr i        System out print  Numbers in Descending Order        for int i   arr length - 1  i  gt   0  i--      System out print        arr i

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I have done it in this manner  I m new in java also in programming    import java util Scanner    public class SortingNumbers    public static void main String   args        Scanner scan1 new Scanner System in       System out print  How many numbers you want to sort          int a scan1 nextInt         int i j k 0     i and j is used in various loops      int num   new int a       int great    new int a        This array elements will be used to store  the number of being greater          Scanner scan2 new Scanner System in       System out println  Enter the numbers           for i 0 i lt a i                num i    scan2 nextInt         for  i 0 i lt a i              for j 0 j lt a j                  if num i  gt num j       first time when executes this line  i 0 and j 0 and then i 0 j 1 and so on  each time it finishes second for loop the value of num i  changes                  k          great i  k       At the end of each for loop  second one  k   contains the total of how many times a number is greater than the others      k 0       And then  again k is forced to 0  so that it can collect  the total of how many times a number is greater  for another number       System out print  Ascending Order          for i 0 i lt a i            for j 0 j lt a j                if great j   i  System out print num j          there is a fixed value for each great j  that is  from 0 upto number of elements input numbers       System out print  Discending Order          for i 0 i lt  a i            for j 0 j lt a j                if great j   a-i  System out print  num j

User · Answer

package pack2   import java util Scanner   public class group    public static void main String   args           TODO Auto-generated method stub     Scanner data  new Scanner System in       int value    new int 5       int temp 0 i 0 j 0      System out println  Enter 5 element of array        for i 0 i lt 5 i        value i  data nextInt         for i 0 i lt 5 i                for j i j lt 5 j                 if value i  gt value j                  temp value i          value i  value j          value j  temp                               System out println  Increasing Order           for i 0 i lt 5 i               System out println    value i

User · Answer

Three possible solutions come to my mind   1  Reverse the order     convert the arr to list first Collections reverse listWithNumbers   System out print  Numbers in Descending Order      listWithNumbers     2  Iterate backwards and print it   Arrays sort arr   System out print  Numbers in Descending Order       for int i   arr length - 1  i  gt   0  i--     System out print       arr i        3  Sort it with  oposite  comparator   Arrays sort arr  new Comparator lt Integer gt        int compare Integer i1  Integer i2          return i2 - i1              or Collections reverseOrder    could be used instead System out print  Numbers in Descending Order       for int i   0  i  lt  arr length  i       System out print       arr i

User · Answer

You could take the ascending array and output in reverse order  so replace the second for statement with   for int i   arr length - 1  i  gt   0  i--                If you have Apache s commons-lang on the classpath  it has a method ArrayUtils reverse int    that you can use   By the way  you probably don t want to sort it in every cycle of the for loop

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public static void main String   args              Scanner input  new Scanner System in             System out print  enter how many              int num  input nextInt        int   arr  new int  num       for int b 0 b lt arr length b        System out print  enter no      b 1            arr b  input nextInt               for  int i 0  i lt arr length i              for  int k i k lt arr length k               if arr i   gt  arr k              int temp arr k           arr k  arr i           arr i  temp                                     System out println                     n output t accending order          for  int i   arr           System out println i

User · Answer

Arrays sort arr  Collections reverseOrder     for int i   0  i  lt  arr length  i         System out print       arr i        And move Arrays sort   out of that for loop   You are sorting the same array on each iteration

[java] Ascending and Descending Number Order in java

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