Java division by zero doesnt throw an ArithmeticException - why

Question

Why doesn t this code throw an ArithmeticException  Take a look  public class NewClass        public static void main String   args               TODO code application logic here         double tab      1 2  3 4  0 0  5 6            try               for  int i   0  i  lt  tab length  i                      tab i    1 0   tab i                           catch  ArithmeticException ae                System out println  quot ArithmeticException occured  quot                       I have no idea

User · Accepted Answer

Why can t you just check it yourself and throw an exception if that is what you want       try           for  int i   0  i  lt  tab length  i                  tab i    1 0   tab i                if  tab i     Double POSITIVE INFINITY                        tab i     Double NEGATIVE INFINITY                  throw new ArithmeticException                    catch  ArithmeticException ae            System out println  ArithmeticException occured

User · Answer

When divided by zero   If you divide double by 0  JVM will show Infinity   public static void main String    args   double a 10 00  System out println a 0       Console  Infinity If you divide int by 0  then JVM will throw Arithmetic Exception   public static void main String    args       int a 10      System out println a 0       Console  Exception in thread  main  java lang ArithmeticException    by zero

User · Answer

0 0 is a double literal and this is not considered as absolute zero  No exception because it is considered that the double variable large enough to hold the values representing near infinity

User · Answer

IEEE 754 defines 1 0   0 0 as Infinity and -1 0   0 0 as -Infinity and 0 0   0 0 as NaN  By the way  floating point values also have -0 0 and so 1 0  -0 0 is -Infinity  Integer arithmetic doesn t have any of these values and throws an Exception instead  To check for all possible values  e g  NaN  0 0  -0 0  which could produce a non finite number you can do the following  if  Math abs tab i    1   tab i    lt  Double POSITIVE INFINITY     throw new ArithmeticException  quot Not finite quot

User · Answer

There is a trick  Arithmetic exceptions only happen when you are playing around with integers and only during   or   operation   If there is any floating point number in an arithmetic operation  internally all integers will get converted into floating point  This may help you to remember things easily

User · Answer

This is behaviour of floating point arithmetic is by specification  Excerpt from the specification     15 17 2  Division Operator        Division of a nonzero finite value by a zero results in a signed infinity  The sign is determined by the rule stated above

User · Answer

That s because you are dealing with floating point numbers  Division by zero returns Infinity  which is similar to NaN  not a number    If you want to prevent this  you have to test tab i  before using it  Then you can throw your own exception  if you really need it

User · Answer

Java will not throw an exception if you divide by float zero  It will detect a run-time error only if you divide by integer zero not double zero   If you divide by 0 0  the result will be INFINITY

[java] Java division by zero doesnt throw an ArithmeticException - why?

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