Extract digits from string - StringUtils Java

Question

I have a String and I want to extract the  only  sequence of digits in the string    Example  helloThisIsA1234Sample  I want the 1234  It s a given that the sequence of digits will occur only once within the string but not in the same position    for those who will ask  I have a server name and need to extract a specific number within it   I would like to use the StringUtils class from Apache commomns      Thanks

User · Answer

Use a regex such as   0-9  to remove all non-digits   From there  just use Integer parseInt String

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Just one line   int value   Integer parseInt string replaceAll    0-9

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You can split the string and compare with each character  public static String extractNumberFromString String source        StringBuilder result   new StringBuilder 100       for  char ch   source toCharArray              if  ch  gt    0   amp  amp  ch  lt    9                 result append ch                        return result toString        Testing Code       Test     public void test extractNumberFromString         String numberString   NumberUtil extractNumberFromString   61 415 987 636        assertThat numberString  equalTo  61415987636          numberString   NumberUtil extractNumberFromString   02 9295-987-636        assertThat numberString  equalTo  029295987636          numberString   NumberUtil extractNumberFromString   02         amp       lt  gt       9295-     987-636        assertThat numberString  equalTo  029295987636

User · Answer

try this    String s    helloThisIsA1234Sample   s   s replaceAll    D          This means  replace all occurrences of digital characters  0 -9  by an empty string

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String line    This order was32354 placed for QT   OK            String regex        d              String   str   line split regex            System out println str 1

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Use this code numberOnly will contain your desired output       String str  sdfvsdf68fsdfsf8999fsdf09      String numberOnly  str replaceAll    0-9

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String s  as234dfd423   for int i 0 i lt s length   i           char c s charAt i         char d s charAt i        if   a   lt   c  amp  amp  c  lt    z            System out println  String -  c        else  if   0   lt   d  amp  amp  d  lt    9              System out println  number -  d           output -  number -4 number -3 number -4 String -d String -f String -d number -2 number -3

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You can use the following regular expression   string split      0  replace     d  g

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You can try this     String str  java123java456     String out       for int i 0 i lt str length   i            int a str codePointAt i        if a gt  49 amp  amp a lt  57                     out out str charAt i                  System out println out

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Simple  python code for separating  the digits in string     s  rollnumber99mixedin447    list filter lambda c  c  gt    0  and c  lt    9    x for x in s

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You can also use java util Scanner   new Scanner str  useDelimiter      d     nextInt    You can use next   instead of nextInt   to get the digits as string   You can check for the presence of number using hasNextInt   on the Scanner

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I ve created a JUnit Test class as a additional knowledge info  for the same issue  Hope you ll be finding this helpful      public class StringHelper         Separate words from String which has gigits         public String drawDigitsFromString String strValue               String str   strValue trim                String digits                 for  int i   0  i  lt  str length    i                      char chrs   str charAt i                                 if  Character isDigit chrs                       digits   digits chrs                            return digits                    And JUnit Test case is    public class StringHelperTest       StringHelper helper            Before         public void before                helper   new StringHelper                        Test     public void testDrawDigitsFromString            assertEquals  187111   helper drawDigitsFromString  TCS187TCS111

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You can use the following Code to retain Integers from String   String text  Hello1010   System out println CharMatcher digit   retainFrom text      Will give you the Following Output   1010

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Extending the best answer for finding floating point numbers         String str  2 53GHz          String decimal values  str replaceAll    0-9                   System out println decimal values

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A very simple solution  if separated by comma or if not separated by comma  public static void main String   args         String input    a 1 b 2 c 3 d 4       input   input replaceAll                String alpha          String num            char   c arr   input toCharArray         for char c  c arr            if Character isDigit c                 alpha   alpha   c                    else               num   num c                       System out println  Alphabet     alpha       System out println  num     num

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I always like using Guava String utils or similar for these kind of problems   String theDigits   CharMatcher inRange  0    9   retainFrom  abc12 3def       123

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You can use str   str replaceAll    D

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Try this approach if you have symbols and you want just numbers       String s        9823l Azad9927      738        System out println s s replaceAll    0-9              StringTokenizer tok   new StringTokenizer s           amp    -        gt  lt          String s1           while tok hasMoreTokens             s1   tok nextToken              System out println s1

[java] Extract digits from string - StringUtils Java

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