I am using the Long primitive type which increments by 1 whenever my 'generateNumber'method called. What happens if Long reaches to his maximum limit? will throw any exception or will reset to minimum value? here is my sample code:
class LongTest {
private static long increment;
public static long generateNumber(){
++increment;
return increment;
}
}
This question is related to
java
Exceding the maximum value of a long doesnt throw an exception, instead it cicles back. If you do this:
Long.MAX_VALUE + 1
you will notice that the result is the equivalent to Long.MIN_VALUE.
From here: java number exceeds long.max_value - how to detect?
It will overflow and wrap around to Long.MIN_VALUE
.
Its not too likely though. Even if you increment 1,000,000 times per second it will take about 300,000 years to overflow.
Ranges from -9,223,372,036,854,775,808 to +9,223,372,036,854,775,807.
It will start from -9,223,372,036,854,775,808
Long.MIN_VALUE.
Source: Stackoverflow.com