Java Long primitive type maximum limit

Question

I am using the Long primitive type which increments by 1 whenever my  generateNumber method called  What happens if Long reaches to his maximum limit  will throw any exception or will reset to minimum value  here is my sample code   class LongTest      private static long increment     public static long generateNumber             increment         return increment

User · Answer

Exceding the maximum value of a long doesnt throw an exception, instead it cicles back. If you do this:

Long.MAX_VALUE + 1

you will notice that the result is the equivalent to Long.MIN_VALUE.

From here: java number exceeds long.max_value - how to detect?

User · Answer

It will overflow and wrap around to Long MIN VALUE   Its not too likely though  Even if you increment 1 000 000 times per second it will take about 300 000 years to overflow

User · Answer

Long MAX VALUE is 9 223 372 036 854 775 807   If you were executing your function once per nanosecond  it would still take over 292 years to encounter this situation according to this source   When that happens  it ll just wrap around to Long MIN VALUE  or -9 223 372 036 854 775 808 as others have said

User · Answer

Ranges from -9 223 372 036 854 775 808 to  9 223 372 036 854 775 807    It will start from -9 223 372 036 854 775 808   Long MIN VALUE

[java] Java Long primitive type maximum limit

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