[go] Is there a way to do repetitive tasks at intervals?

Is there a way to do repetitive background tasks in Go? I'm thinking of something like Timer.schedule(task, delay, period) in Java. I know I can do this with a goroutine and Time.sleep(), but I'd like something that easily stopped.

Here's what I got, but looks ugly to me. Is there a cleaner/better way?

func oneWay() {
    var f func()
    var t *time.Timer

    f = func () {
        fmt.Println("doing stuff")
        t = time.AfterFunc(time.Duration(5) * time.Second, f)
    }

    t = time.AfterFunc(time.Duration(5) * time.Second, f)

    defer t.Stop()

    //simulate doing stuff
    time.Sleep(time.Minute)
}

This question is related to go

The answer is


If you want to stop it in any moment ticker

ticker := time.NewTicker(500 * time.Millisecond)
go func() {
    for range ticker.C {
        fmt.Println("Tick")
    }
}()
time.Sleep(1600 * time.Millisecond)
ticker.Stop()

If you do not want to stop it tick:

tick := time.Tick(500 * time.Millisecond)
for range tick {
    fmt.Println("Tick")
}

How about something like

package main

import (
    "fmt"
    "time"
)

func schedule(what func(), delay time.Duration) chan bool {
    stop := make(chan bool)

    go func() {
        for {
            what()
            select {
            case <-time.After(delay):
            case <-stop:
                return
            }
        }
    }()

    return stop
}

func main() {
    ping := func() { fmt.Println("#") }

    stop := schedule(ping, 5*time.Millisecond)
    time.Sleep(25 * time.Millisecond)
    stop <- true
    time.Sleep(25 * time.Millisecond)

    fmt.Println("Done")
}

Playground


I use the following code:

package main

import (
    "fmt"
    "time"
)

func main() {
    now := time.Now()
    fmt.Println("\nToday:", now)

    after := now.Add(1 * time.Minute)
    fmt.Println("\nAdd 1 Minute:", after)

    for {
        fmt.Println("test")
        time.Sleep(10 * time.Second)

        now = time.Now()

        if now.After(after) {
            break
        }
    }

    fmt.Println("done")
}

It is more simple and works fine to me.


A broader answer to this question might consider the Lego brick approach often used in Occam, and offered to the Java community via JCSP. There is a very good presentation by Peter Welch on this idea.

This plug-and-play approach translates directly to Go, because Go uses the same Communicating Sequential Process fundamentals as does Occam.

So, when it comes to designing repetitive tasks, you can build your system as a dataflow network of simple components (as goroutines) that exchange events (i.e. messages or signals) via channels.

This approach is compositional: each group of small components can itself behave as a larger component, ad infinitum. This can be very powerful because complex concurrent systems are made from easy to understand bricks.

Footnote: in Welch's presentation, he uses the Occam syntax for channels, which is ! and ? and these directly correspond to ch<- and <-ch in Go.


If you do not care about tick shifting (depending on how long did it took previously on each execution) and you do not want to use channels, it's possible to use native range function.

i.e.

package main

import "fmt"
import "time"

func main() {
    go heartBeat()
    time.Sleep(time.Second * 5)
}

func heartBeat() {
    for range time.Tick(time.Second * 1) {
        fmt.Println("Foo")
    }
}

Playground


Check out this library: https://github.com/robfig/cron

Example as below:

c := cron.New()
c.AddFunc("0 30 * * * *", func() { fmt.Println("Every hour on the half hour") })
c.AddFunc("@hourly",      func() { fmt.Println("Every hour") })
c.AddFunc("@every 1h30m", func() { fmt.Println("Every hour thirty") })
c.Start()