I am getting a parsing exception while I am trying the following code:
String date="Sat Jun 01 12:53:10 IST 2013";
SimpleDateFormat sdf=new SimpleDateFormat("MMM d, yyyy HH:mm:ss");
Date currentdate;
currentdate=sdf.parse(date);
System.out.println(currentdate);
Exception:
Exception in thread "main" java.text.ParseException: Unparseable date: "Sat Jun 01 12:53:10 IST 2013" at com.ibm.icu.text.DateFormat.parse(DateFormat.java:510)
Input: Sat Jun 01 12:53:10 IST 2013
Expected output: Jun 01,2013 12:53:10
How to solve this?
This question is related to
java
simpledateformat
parseexception
Update your format to:
SimpleDateFormat sdf=new SimpleDateFormat("E MMM dd hh:mm:ss Z yyyy");
String date="Sat Jun 01 12:53:10 IST 2013";
SimpleDateFormat sdf=new SimpleDateFormat("E MMM dd HH:mm:ss z yyyy");
Date currentdate=sdf.parse(date);
SimpleDateFormat sdf2=new SimpleDateFormat("MMM dd,yyyy HH:mm:ss");
System.out.println(sdf2.format(currentdate));
I found simple solution to get current date without any parsing error.
Calendar calendar;
calendar = Calendar.getInstance();
String customDate = "" + calendar.get(Calendar.YEAR) + "-" + (calendar.get(Calendar.MONTH) + 1) + "-" + calendar.get(Calendar.DAY_OF_MONTH);
Check your Pattern (DD-MMM-YYYY) and the input for the parse("29-11-2018") method. Input to the parse method should follow : DD-MMM-YYYY i,e. 21-AUG-2019
In My Code:
String pattern = "DD-MMM-YYYY";
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern);
try {
startDate = simpleDateFormat.parse("29-11-2018");// here no pattern match
endDate = simpleDateFormat.parse("28-AUG-2019");// Ok
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String date="Sat Jun 01 12:53:10 IST 2013";
SimpleDateFormat sdf=new SimpleDateFormat("MMM d, yyyy HH:mm:ss");
This patterns does not tally with your input String which occurs the exception.
You need to use following pattern to get the work done.
E MMM dd HH:mm:ss z yyyy
Following code will help you to skip the exception.
SimpleDateFormat
is used.
String date="Sat Jun 01 12:53:10 IST 2013"; // Input String
SimpleDateFormat simpleDateFormat=new SimpleDateFormat("E MMM dd HH:mm:ss z yyyy"); // Existing Pattern
Date currentdate=simpleDateFormat.parse(date); // Returns Date Format,
SimpleDateFormat simpleDateFormat1=new SimpleDateFormat("MMM dd,yyyy HH:mm:ss"); // New Pattern
System.out.println(simpleDateFormat1.format(currentdate)); // Format given String to new pattern
// outputs: Jun 01,2013 12:53:10
I needed to add a ParsePosition
expression to the parse method of class SimpleDateFormat
:
simpledateformat.parse(mydatestring, new ParsePosition(0));
Instead a format such as yours, use ISO 8601 standard formats for exchanging date-time values as text.
The java.time classes use the standard ISO 8601 formats by default when parsing/generating strings.
Specify a proper time zone name in the format of continent/region
, such as America/Montreal
, Africa/Casablanca
, or Pacific/Auckland
. Never use the 3-4 letter abbreviation such as EST
or IST
as they are not true time zones, not standardized, and not even unique(!).
Your IST
could mean Iceland Standard Time, India Standard Time, Ireland Standard Time, or others. The java.time classes are left to merely guessing, as there is no logical solution to this ambiguity.
The modern approach uses the java.time classes.
Define a formatting pattern to match your input strings.
String input = "Sat Jun 01 12:53:10 IST 2013";
DateTimeFormatter f = DateTimeFormatter.ofPattern( "EEE MMM dd HH:mm:ss z uuuu" , Locale.US );
ZonedDateTime zdt = ZonedDateTime.parse( input , f );
zdt.toString(): 2013-06-01T12:53:10Z[Atlantic/Reykjavik]
If your input was not intended for Iceland, you should pre-parse the string to adjust to a proper time zone name. For example, if you are certain the input was intended for India, change IST
to Asia/Kolkata
.
String input = "Sat Jun 01 12:53:10 IST 2013".replace( "IST" , "Asia/Kolkata" );
DateTimeFormatter f = DateTimeFormatter.ofPattern( "EEE MMM dd HH:mm:ss z uuuu" , Locale.US );
ZonedDateTime zdt = ZonedDateTime.parse( input , f );
zdt.toString(): 2013-06-01T12:53:10+05:30[Asia/Kolkata]
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date
, Calendar
, & SimpleDateFormat
.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.*
classes.
Where to obtain the java.time classes?
The ThreeTen-Extra project extends java.time with additional classes. This project is a proving ground for possible future additions to java.time. You may find some useful classes here such as Interval
, YearWeek
, YearQuarter
, and more.
Pattern is wrong
String date="Sat Jun 01 12:53:10 IST 2013";
SimpleDateFormat sdf=new SimpleDateFormat("E MMM dd hh:mm:ss Z yyyy");
Date currentdate;
currentdate=sdf.parse(date);
System.out.println(currentdate);
Source: Stackoverflow.com