[angularjs] Can angularjs routes have optional parameter values?

Can I set a route with optional params (same template and controller, but some params should be ignored if they don't exist?

So instead of writing the following two rules, have only one?

module.config(['$routeProvider', function($routeProvider) {
    $routeProvider.
     when('/users/', {templateUrl: 'template.tpl.html', controller: myCtrl}).            
     when('/users/:userId', {templateUrl: 'template.tpl.html', controller: myCtrl})
}]);

Something like this ([this param is optional])

when('/users[/:userId]', {templateUrl: 'template.tpl.html', controller: myCtrl})
//note: this previous doesn't work

I couldn't find anything in their documentation.

This question is related to angularjs angularjs-routing

The answer is


Like @g-eorge mention, you can make it like this:

module.config(['$routeProvider', function($routeProvider) {
$routeProvider.
  when('/users/:userId?', {templateUrl: 'template.tpl.html', controller: myCtrl})
}]);

You can also make as much as u need optional parameters.


Please see @jlareau answer here: https://stackoverflow.com/questions/11534710/angularjs-how-to-use-routeparams-in-generating-the-templateurl

You can use a function to generate the template string:

var app = angular.module('app',[]);

app.config(
    function($routeProvider) {
        $routeProvider.
            when('/', {templateUrl:'/home'}).
            when('/users/:user_id', 
                {   
                    controller:UserView, 
                    templateUrl: function(params){ return '/users/view/' + params.user_id;   }
                }
            ).
            otherwise({redirectTo:'/'});
    }
);

Actually I think OZ_ may be somewhat correct.

If you have the route '/users/:userId' and navigate to '/users/' (note the trailing /), $routeParams in your controller should be an object containing userId: "" in 1.1.5. So no the paramater userId isn't completely ignored, but I think it's the best you're going to get.