How to get the path of running java program

Question

Is there a way to get the path of main class of the running java program   structure is  D    ---Project         ------bin         ------src   I want to get the path as D  Project bin    I tried System getProperty  java class path    but the problem is  if I run like   java -classpath D  Project bin D  Project src   Main  Output  Getting   D  Project bin D  Project src  Want      D  Project bin   Is there any way to do this              EDIT         Got the solution here  Solution 1  By Jon Skeet   package foo   public class Test       public static void main String   args                ClassLoader loader   Test class getClassLoader            System out println loader getResource  foo Test class               This printed out   file  C  Users Jon Test foo Test class     Solution 2  By Erickson   URL main   Main class getResource  Main class    if    file  equalsIgnoreCase main getProtocol       throw new IllegalStateException  Main class is not stored in a file     File path   new File main getPath       Note that most class files are assembled into JAR files so this won t work in every case  hence the IllegalStateException   However  you can locate the JAR that contains the class with this technique  and you can get the content of the class file by substituting a call to getResourceAsStream   in place of getResource    and that will work whether the class is on the file system or in a JAR

User · Accepted Answer

Try this code   final File f   new File MyClass class getProtectionDomain   getCodeSource   getLocation   getPath       replace  MyClass  with your class containing the main method   Alternatively you can also use   System getProperty  java class path     Above mentioned System property provides      Path used to find directories and JAR archives containing class files    Elements of the class path are separated by a platform-specific   character specified in the path separator property

User · Answer

You actually do not want to get the path to your main class  According to your example you want to get the current working directory  i e  directory where your program started  In this case you can just say new File      getAbsolutePath

User · Answer

Use  System getProperty  java class path     see http   docs oracle com javase tutorial essential environment sysprop html  You can also split it into it s elements easily  String classpath   System getProperty  java class path    String   classpathEntries   classpath split File pathSeparator

User · Answer

ClassLoader cl   ClassLoader getSystemClassLoader         URL   urls     URLClassLoader cl  getURLs         for URL url  urls           System out println url getFile

[java] How to get the path of running java program

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