How to read strings from a Scanner in a Java console application

Question

import java util Scanner  class MyClass       public static void main String args                  Scanner scanner   new Scanner System in           int employeeId  supervisorId          String name          System out println  Enter employee ID             employeeId   scanner nextInt            System out println  Enter employee name             name   scanner next            System out println  Enter supervisor ID             supervisorId   scanner nextInt              I got this exception while trying to enter a first name and last name   Enter employee ID  101 Enter employee name  firstname lastname Enter supervisor ID  Exception in thread  main  java util InputMismatchException     at java util Scanner throwFor Unknown Source      at java util Scanner next Unknown Source      at java util Scanner nextInt Unknown Source      at java util Scanner nextInt Unknown Source      at com controller Menu  lt init gt  Menu java 61      at com tests Employeetest main Employeetest java 17    but its working on if I only enter the first name   Enter employee ID  105 Enter employee name  name Enter supervisor ID  501   What I want is to read the full string whether it is given as name or as firstname lastname  What s the problem here

User · Answer

Replace   System out println  Enter EmployeeName                      ename  scanner next       with   System out println  Enter EmployeeName                      ename  scanner nextLine       This is because next   grabs only the next token  and the space acts as a delimiter between the tokens  By this  I mean that the scanner reads the input   firstname lastname  as two separate tokens  So in your example  ename would be set to firstname and the scanner is attempting to set the supervisorId to lastname

User · Answer

Scanner scanner   new Scanner System in   int employeeId  supervisorId  String name  System out println  Enter employee ID     employeeId   scanner nextInt    scanner nextLine      This is needed to pick up the new line System out println  Enter employee name     name   scanner nextLine    System out println  Enter supervisor ID     supervisorId   scanner nextInt      Calling nextInt   was a problem as it didn t pick up the new line  when you hit enter   So  calling scanner nextLine   after that does the work

User · Answer

What you can do is use delimeter as new line  Till you press enter key you will be able to read it as string    Scanner sc   new Scanner System in   sc useDelimiter System getProperty  line separator       Hope this helps

User · Answer

You are entering a null value to nextInt  it will fail if you give a null value     i have added a null check to the piece of code  Try this code   import java util Scanner  class MyClass        public static void main String args                      Scanner scanner   new Scanner System in                   int eid sid                  String ename                  System out println  Enter Employeeid                          eid  scanner nextInt                     System out println  Enter EmployeeName                          ename  scanner next                     System out println  Enter SupervisiorId                         if scanner nextLine    null amp  amp scanner nextLine          null check                      sid scanner nextInt                            null check

[java] How to read strings from a Scanner in a Java console application?

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