How to find the duration of difference between two dates in java

Question

I have two objects of DateTime  which need to find the duration of their difference  I have the following code but not sure how to continue it to get to the expected results as following  Example        11 03 14 09 30 58       11 03 14 09 33 43       elapsed time is 02 minutes and 45 seconds       -----------------------------------------------------       11 03 14 09 30 58        11 03 15 09 30 58       elapsed time is a day       -----------------------------------------------------       11 03 14 09 30 58        11 03 16 09 30 58       elapsed time is two days       -----------------------------------------------------       11 03 14 09 30 58        11 03 16 09 35 58       elapsed time is two days and 05 minutes         Code      String dateStart    quot 11 03 14 09 29 58 quot       String dateStop    quot 11 03 14 09 33 43 quot        Custom date format     SimpleDateFormat format   new SimpleDateFormat  quot yy MM dd HH mm ss quot         Date d1   null      Date d2   null      try           d1   format parse dateStart           d2   format parse dateStop         catch  ParseException e            e printStackTrace                  Get msec from each  and subtract      long diff   d2 getTime   - d1 getTime        long diffSeconds   diff   1000   60      long diffMinutes   diff    60   1000    60      long diffHours   diff    60   60   1000       System out println  quot Time in seconds   quot    diffSeconds    quot  seconds  quot        System out println  quot Time in minutes   quot    diffMinutes    quot  minutes  quot        System out println  quot Time in hours   quot    diffHours    quot  hours  quot

User · Accepted Answer

try the following             Date dt2   new DateAndTime   getCurrentDateTime             long diff   dt2 getTime   - dt1 getTime            long diffSeconds   diff   1000   60          long diffMinutes   diff    60   1000    60          long diffHours   diff    60   60   1000           int diffInDays    int    dt2 getTime   - dt1 getTime       1000   60   60   24             if  diffInDays  gt  1                System err println  Difference in number of days  2        diffInDays               return false            else if  diffHours  gt  24                 System err println   gt 24                return false            else if   diffHours    24   amp  amp   diffMinutes  gt   1                 System err println  minutes                return false                    return true

User · Answer

This is a program I wrote  which gets the number of days between 2 dates no time here    import java util Scanner  public class HelloWorld    public static void main String args        Scanner s   new Scanner System in     System out print  Enter starting date separated by dots        String inp1   s nextLine      System out print  Enter ending date separated by dots        String inp2   s nextLine      int   nodim        0     31     28     31     30     31     30     31     31     30     31     30     31        String   inpArr1   split inp1     String   inpArr2   split inp2     int d1   Integer parseInt inpArr1 0      int m1   Integer parseInt inpArr1 1      int y1   Integer parseInt inpArr1 2      int d2   Integer parseInt inpArr2 0      int m2   Integer parseInt inpArr2 1      int y2   Integer parseInt inpArr2 2      if  y1   4    0  nodim 2    29    int diff   m1    m2  amp  amp  y1    y2   d2 -  d1 - 1     nodim m1  -  d1 - 1      int mm1   m1   1  mm2   m2 - 1  yy1   y1  yy2   y2    for    yy1  lt   yy2  yy1    mm1   1       mm2   yy1    yy2    m2 - 1    12     if  yy1   4    0  nodim 2    29     else nodim 2    28     if  mm2    0        mm2   12      yy2   yy2 - 1          for    mm1  lt   mm2  amp  amp  yy1  lt   yy2  mm1    diff   diff   nodim mm1         System out print  No  of days from     inp1     to     inp2     is     diff       public static String   split String s      String   retval                                s   s          s   s          for  int i   0  i  lt   2  i         retval i    s substring 0  s indexOf           s   s substring  s indexOf        1   s length           return retval         http   pastebin com HRsjTtUf

User · Answer

You can create a method like  public long getDaysBetweenDates Date d1  Date d2   return TimeUnit MILLISECONDS toDays d1 getTime   - d2 getTime         This method will return the number of days between the 2 days

User · Answer

The date difference conversion could be handled in a better way using Java built-in class  TimeUnit  It provides utility methods to do that   Date startDate      Set start date Date endDate        Set end date  long duration    endDate getTime   - startDate getTime     long diffInSeconds   TimeUnit MILLISECONDS toSeconds duration   long diffInMinutes   TimeUnit MILLISECONDS toMinutes duration   long diffInHours   TimeUnit MILLISECONDS toHours duration   long diffInDays   TimeUnit MILLISECONDS toDays duration

User · Answer

It worked for me can try with this  hope it will be helpful   Let me know if any concern    Date startDate   java util Calendar getInstance   getTime      set your start time Date endDate   java util Calendar getInstance   getTime       set  your end time  long duration   endDate getTime   - startDate getTime      long diffInSeconds   TimeUnit MILLISECONDS toSeconds duration   long diffInMinutes   TimeUnit MILLISECONDS toMinutes duration   long diffInHours   TimeUnit MILLISECONDS toHours duration   long diffInDays   TimeUnit MILLISECONDS toDays duration    Toast makeText MainActivity this   Diff            duration   diffInDays   diffInHours   diffInMinutes   diffInSeconds  Toast LENGTH SHORT  show         Toast message for android      System out println  Diff    duration   diffInDays   diffInHours   diffInMinutes   diffInSeconds        Print console message for Java

User · Answer

Here is how the problem can solved in Java 8 just like the answer by shamimz   Source    http   docs oracle com javase tutorial datetime iso period html  LocalDate today   LocalDate now    LocalDate birthday   LocalDate of 1960  Month JANUARY  1    Period p   Period between birthday  today   long p2   ChronoUnit DAYS between birthday  today    System out println  You are     p getYears       years      p getMonths       months  and     p getDays       days old       p2     days total       The code produces output similar to the following   You are 53 years  4 months  and 29 days old   19508 days total    We have to use LocalDateTime http   docs oracle com javase 8 docs api java time LocalDateTime html to get hour minute second differences

User · Answer

As Michael Borgwardt writes in his answer here    int diffInDays    int    newerDate getTime   - olderDate getTime                         1000   60   60   24          Note that this works with UTC dates  so the difference may be a day   off if you look at local dates  And getting it to work correctly with   local dates requires a completely different approach due to daylight   savings time

User · Answer

Use Joda-Time library  DateTime startTime  endTime  Period p   new Period startTime  endTime   long hours   p getHours    long minutes   p getMinutes      Joda Time has a concept of time Interval   Interval interval   new Interval oldTime  new Instant       One more example Date Difference  One more Link  or with Java-8  which integrated Joda-Time concepts   Instant start  end    Duration dur   Duration between start  stop   long hours   dur toHours    long minutes   dur toMinutes

User · Answer

In Java 8  you can make of DateTimeFormatter  Duration  and LocalDateTime  Here is an example   final String dateStart    11 03 14 09 29 58   final String dateStop    11 03 14 09 33 43    final DateTimeFormatter formatter   new DateTimeFormatterBuilder            appendValue ChronoField MONTH OF YEAR  2           appendLiteral               appendValue ChronoField DAY OF MONTH  2           appendLiteral               appendValueReduced ChronoField YEAR  2  2  2000           appendLiteral               appendValue ChronoField HOUR OF DAY  2           appendLiteral               appendValue ChronoField MINUTE OF HOUR  2           appendLiteral               appendValue ChronoField SECOND OF MINUTE  2           toFormatter     final LocalDateTime start   LocalDateTime parse dateStart  formatter   final LocalDateTime stop   LocalDateTime parse dateStop  formatter    final Duration between   Duration between start  stop    System out println start   System out println stop   System out println formatter format start    System out println formatter format stop    System out println between   System out println between get ChronoUnit SECONDS

User · Answer

I solved the similar problem using a simple method recently    public static void main String   args  throws IOException  ParseException           TimeZone utc   TimeZone getTimeZone  UTC            Calendar calendar   Calendar getInstance utc           Date until   calendar getTime            calendar add Calendar DAY OF MONTH  -7           Date since   calendar getTime            long durationInSeconds    TimeUnit MILLISECONDS toSeconds until getTime   - since getTime              long SECONDS IN A MINUTE   60          long MINUTES IN AN HOUR   60          long HOURS IN A DAY   24          long DAYS IN A MONTH   30          long MONTHS IN A YEAR   12           long sec    durationInSeconds  gt   SECONDS IN A MINUTE    durationInSeconds   SECONDS IN A MINUTE   durationInSeconds          long min    durationInSeconds    SECONDS IN A MINUTE   gt   MINUTES IN AN HOUR   durationInSeconds MINUTES IN AN HOUR   durationInSeconds          long hrs    durationInSeconds    MINUTES IN AN HOUR   gt   HOURS IN A DAY   durationInSeconds   HOURS IN A DAY   durationInSeconds          long days    durationInSeconds    HOURS IN A DAY   gt   DAYS IN A MONTH   durationInSeconds   DAYS IN A MONTH   durationInSeconds          long months    durationInSeconds   DAYS IN A MONTH   gt   MONTHS IN A YEAR   durationInSeconds   MONTHS IN A YEAR   durationInSeconds          long years    durationInSeconds    MONTHS IN A YEAR            String duration   getDuration sec min hrs days months years           System out println duration             private static String getDuration long secs  long mins  long hrs  long days  long months  long years            StringBuffer sb   new StringBuffer            String EMPTY STRING               sb append years  gt  0   years    years  gt  1     years       year     EMPTY STRING           sb append months  gt  0   months    months  gt  1     months       month     EMPTY STRING           sb append days  gt  0   days    days  gt  1     days       day     EMPTY STRING           sb append hrs  gt  0   hrs    hrs  gt  1     hours       hour     EMPTY STRING           sb append mins  gt  0   mins    mins  gt  1     mins       min     EMPTY STRING           sb append secs  gt  0   secs    secs  gt  1     secs       secs     EMPTY STRING           sb append  ago            return sb toString            And as expected it prints  7 days ago

User · Answer

calculating the difference b w startDate and endDate         String startDate    01-01-2016           String endDate   simpleDateFormat format currentDate            date1   simpleDateFormat parse startDate           date2   simpleDateFormat parse endDate            long getDiff   date2 getTime   - date1 getTime                using TimeUnit class from java util concurrent package         long getDaysDiff   TimeUnit MILLISECONDS toDays getDiff     How to calculate difference between two dates in Java

User · Answer

with reference to shamim s answer update here is a method that does the task without using any third party library  Just copy the method and use  public static String getDurationTimeStamp String date             String timeDifference                  date formatter as per the coder need         SimpleDateFormat sdf   new SimpleDateFormat  yyyy-MM-dd HH mm ss               parse the string date-ti            me to Date object         Date startDate   null          try               startDate   sdf parse date             catch  ParseException e                e printStackTrace                         end date will be the current system time to calculate the lapse time difference           if needed  coder can add end date to whatever date         Date endDate   new Date             System out println startDate           System out println endDate              get the time difference in milliseconds         long duration   endDate getTime   - startDate getTime               now we calculate the differences in different time units           this long value will be the total time difference in each unit           i e  total difference in seconds  total difference in minutes etc            long diffInSeconds   TimeUnit MILLISECONDS toSeconds duration           long diffInMinutes   TimeUnit MILLISECONDS toMinutes duration           long diffInHours   TimeUnit MILLISECONDS toHours duration           long diffInDays   TimeUnit MILLISECONDS toDays duration              now we create the time stamps depending on the value of each unit that we get           as we do not have the unit in years            we will see if the days difference is more that 365 days  as 365 days   1 year         if  diffInDays  gt  365                  we get the year in integer not in float               ex- 791 365   2 167 in float but it will be 2 years in int             int year    int   diffInDays   365               timeDifference   year     years ago               System out println year     years ago                        if days are not enough to create year then get the days         else if  diffInDays  gt  1                timeDifference   diffInDays     days ago               System out println diffInDays     days ago                        if days value lt 1 then get the hours         else if  diffInHours  gt  1                timeDifference   diffInHours     hours ago               System out println diffInHours     hours ago                        if hours value lt 1 then get the minutes         else if  diffInMinutes  gt  1                timeDifference   diffInMinutes     minutes ago               System out println diffInMinutes     minutes ago                        if minutes value lt 1 then get the seconds         else if  diffInSeconds  gt  1                timeDifference   diffInSeconds     seconds ago               System out println diffInSeconds     seconds ago                       return timeDifference     that s all  Happy Coding

User · Answer

java time Duration I still didn   t feel any of the answers was quite up to date and to the point  So here is the modern answer using Duration from java time  the modern Java date and time API  the answers by MayurB and mkobit mention the same class  but none of them correctly converts to days  hours  minutes and minutes as asked       DateTimeFormatter formatter   DateTimeFormatter ofPattern  quot yy MM dd HH mm ss quot             String dateStart    quot 11 03 14 09 29 58 quot       String dateStop    quot 11 03 14 09 33 43 quot        ZoneId zone   ZoneId systemDefault        ZonedDateTime startDateTime   LocalDateTime parse dateStart  formatter  atZone zone       ZonedDateTime endDateTime   LocalDateTime parse dateStop  formatter  atZone zone            Duration diff   Duration between startDateTime  endDateTime       if  diff isZero              System out println  quot 0 minutes quot          else           long days   diff toDays            if  days    0                System out print  quot  quot    days    quot  days  quot                diff   diff minusDays days                     long hours   diff toHours            if  hours    0                System out print  quot  quot    hours    quot  hours  quot                diff   diff minusHours hours                     long minutes   diff toMinutes            if  minutes    0                System out print  quot  quot    minutes    quot  minutes  quot                diff   diff minusMinutes minutes                     long seconds   diff getSeconds            if  seconds    0                System out print  quot  quot    seconds    quot  seconds  quot                      System out println           Output from this example snippet is   3 minutes 45 seconds  Note that Duration always counts a day as 24 hours  If you want to treat time anomalies like summer time transistions differently  solutions inlcude  1  use ChronoUnit DAYS  2  Use Period  3  Use LocalDateTimeinstead ofZonedDateTime   may be considered a hack   The code above works with Java 8 and with ThreeTen Backport  that backport of java time to Java 6 and 7  From Java 9 it may be possible to write it a bit more nicely using the methods toHoursPart  toMinutesPart and toSecondsPart added there  I will elaborate the explanations further one of the days when I get time  maybe not until next week

User · Answer

This is the code           String date1    07 15 2013           String time1    11 00 01           String date2    07 16 2013           String time2    22 15 10           String format    MM dd yyyy HH mm ss           SimpleDateFormat sdf   new SimpleDateFormat format           Date fromDate   sdf parse date1         time1           Date toDate   sdf parse date2         time2            long diff   toDate getTime   - fromDate getTime            String dateFormat  duration             int diffDays    int   diff    24   60   60   1000            if diffDays gt 0               dateFormat  diffDays   day                      diff -  diffDays    24   60   60   1000            int diffhours    int   diff    60   60   1000            if diffhours gt 0               dateFormat  diffhours   hour                      diff -  diffhours    60   60   1000            int diffmin    int   diff    60   1000            if diffmin gt 0               dateFormat  diffmin   min                      diff -  diffmin    60   1000            int diffsec    int   diff    1000            if diffsec gt 0               dateFormat  diffsec   sec                     System out println dateFormat     and the out is   duration  1 day 11 hour 15 min 9 sec

User · Answer

You can get the difference between two DateTime using this DateTime startDate   DateTime now    DateTime endDate   DateTime now    Days daysBetween   Days daysBetween startDate  endDate   System out println daysBetween toStandardSeconds

User · Answer

Date d2   new Date    Date d1   new Date 1384831803875l    long diff   d2 getTime   - d1 getTime    long diffSeconds   diff   1000   60  long diffMinutes   diff    60   1000    60  long diffHours   diff    60   60   1000   int diffInDays    int  diff    1000   60   60   24    System out println diffInDays    days    System out println diffHours    Hour    System out println diffMinutes    min    System out println diffSeconds    sec

[java] How to find the duration of difference between two dates in java?

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