How to trim a string after a specific character in java

Question

I have a string variable in java having value   String result  34 1 -118 33 n lt  --ABCDEFG-- gt      I want my final string to contain the value   String result  34 1 -118 33     How can I do this  I m new to java programming language   Thanks

User · Answer

You could use   result   result replaceAll   n       or   String   split   result split   n

User · Answer

This is the simplest method you can do and reduce your efforts  just paste this function in your class and call it anywhere   you can do this by creating a substring   simple exampe is here   x000D   x000D  public static String removeTillWord String input  String word        return input substring input indexOf word       removeTillWord  Your String         x000D   x000D   x000D

User · Answer

Try this   String result    34 1 -118 33 n lt  --ABCDEFG-- gt    result   result substring 0  result indexOf   n

User · Answer

How about  Scanner scanner   new Scanner result   String line   scanner nextLine     will contain 34 1 -118 33

User · Answer

Use a Scanner and pass in the delimiter and the original string   result   new Scanner result  useDelimiter   n   next

User · Answer

Assuming you just want everything before  n  or any other literal string char   you should use indexOf   with substring     result   result substring 0  result indexOf   n       If you want to extract the portion before a certain regular expression  you can use split     result   result split regex  2  0       String result    34 1 -118 33 n lt  --ABCDEFG-- gt     System out println result substring 0  result indexOf   n      System out println result split   n   2  0       34 1 -118 33 34 1 -118 33    Obviously  n isn t a meaningful regular expression  I just used it to demonstrate that the second approach also works

User · Answer

There are many good answers  but I would use StringUtils from commons-lang  I find StringUtils substringBefore   more readable than the alternatives   String result   StringUtils substringBefore  34 1 -118 33 n lt  --ABCDEFG-- gt      n

User · Answer

Use regex   result   result replaceAll   n            replaceAll   uses regex to find its target  which I have replaced with  nothing  - effectively deleting the target   The target I ve specified by the regex  n   means  the newline char and everything after

User · Answer

you can use StringTokenizer   StringTokenizer st   new StringTokenizer  34 1 -118 33 n lt  --ABCDEFG-- gt      n    System out println st nextToken       output   34 1 -118 33

User · Answer

You can use   result   result split   n   0

[java] How to trim a string after a specific character in java

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