I have a string variable in java having value:
String result="34.1 -118.33\n<!--ABCDEFG-->";
I want my final string to contain the value:
String result="34.1 -118.33";
How can I do this? I'm new to java programming language.
Thanks,
This question is related to
java
Assuming you just want everything before \n
(or any other literal string/char), you should use indexOf()
with substring()
:
result = result.substring(0, result.indexOf('\n'));
If you want to extract the portion before a certain regular expression, you can use split()
:
result = result.split(regex, 2)[0];
String result = "34.1 -118.33\n<!--ABCDEFG-->";
System.out.println(result.substring(0, result.indexOf('\n')));
System.out.println(result.split("\n", 2)[0]);
34.1 -118.33 34.1 -118.33
(Obviously \n
isn't a meaningful regular expression, I just used it to demonstrate that the second approach also works.)
Try this:
String result = "34.1 -118.33\n<!--ABCDEFG-->";
result = result.substring(0, result.indexOf("\n"));
You could use result = result.replaceAll("\n","");
or
String[] split = result.split("\n");
There are many good answers, but I would use StringUtils
from commons-lang. I find StringUtils.substringBefore()
more readable than the alternatives:
String result = StringUtils.substringBefore("34.1 -118.33\n<!--ABCDEFG-->", "\n");
How about
Scanner scanner = new Scanner(result);
String line = scanner.nextLine();//will contain 34.1 -118.33
you can use StringTokenizer:
StringTokenizer st = new StringTokenizer("34.1 -118.33\n<!--ABCDEFG-->", "\n");
System.out.println(st.nextToken());
output:
34.1 -118.33
Use regex:
result = result.replaceAll("\n.*", "");
replaceAll()
uses regex to find its target, which I have replaced with "nothing" - effectively deleting the target.
The target I've specified by the regex \n.*
means "the newline char and everything after"
Use a Scanner
and pass in the delimiter and the original string:
result = new Scanner(result).useDelimiter("\n").next();
This is the simplest method you can do and reduce your efforts. just paste this function in your class and call it anywhere:
you can do this by creating a substring.
simple exampe is here:
public static String removeTillWord(String input, String word) {
return input.substring(input.indexOf(word));
}
removeTillWord("Your String", "\");
_x000D_
Source: Stackoverflow.com