Is there any in-built method in Java where you can find the user input's type whether it is positive, or negative and so on? The code below doesn't work. I am trying to find a way to input any in-built method that can do it at the if statement.
import java.util.Scanner;
public class Compare {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int number = input.nextInt();
if(number == int)
System.out.println("Number is natural and positive.");
}
}
This question is related to
java
(You should you as Else-If
statement to check the for the three different state (positive, negative, 0)
Here is a simple example (excludes the possibility of non-integer values)
import java.util.Scanner;
public class Compare {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number: ");
int number = input.nextInt();
if( number == 0)
{ System.out.println("Number is equal to zero"); }
else if (number > 0)
{ System.out.println("Number is positive"); }
else
{ System.out.println("Number is negative"); }
}
}
What about using the following:
int number = input.nextInt();
if (number < 0) {
// negative
} else {
// it's a positive
}
Use like below code.
if(number >=0 ) {
System.out.println("Number is natural and positive.");
}
For integers you can use Integer.signum()
Returns the signum function of the specified int value. (The return value is -1 if the specified value is negative; 0 if the specified value is zero; and 1 if the specified value is positive.)
You could use if(number >= 0)
. The fact that you use int number = input.nextInt();
makes sure that it has to be an Integer.
Source: Stackoverflow.com