How would I save a registered Variable to a file? I took this from the tutorial:
- hosts: web_servers
tasks:
- shell: /usr/bin/foo
register: foo_result
ignore_errors: True
- shell: /usr/bin/bar
when: foo_result.rc == 5
How would I save foo_result
variable to a file e.g. foo_result.log
using ansible?
This question is related to
ansible
ansible-playbook
---
- hosts: all
tasks:
- name: Gather Version
debug:
msg: "The server Operating system is {{ ansible_distribution }} {{ ansible_distribution_major_version }}"
- name: Write Version
local_action: shell echo "This is {{ ansible_distribution }} {{ ansible_distribution_major_version }}" >> /tmp/output
A local action will run once for each remote host (in parallel). If you want a unique file per host, make sure to put the inventory_hostname as part of the file name.
- local_action: copy content={{ foo_result }} dest=/path/to/destination/{{ inventory_hostname }}file
If you instead want a single file with all host's information, one way is to have a serial task (don't want to append in parallel) and then append to the file with a module (lineinfile is capable, or could pipe with a shell command)
- hosts: web_servers
serial: 1
tasks:
- local_action: lineinfile line={{ foo_result }} path=/path/to/destination/file
Alternatively, you can add a second play/role/task to the playbook which runs against only local host. Then access the variable from each of the hosts where the registration command ran inside a template Access Other Hosts Variables Docs Template Module Docs
I am using Ansible 1.9.4 and this is what worked for me -
- local_action: copy content="{{ foo_result.stdout }}" dest="/path/to/destination/file"
More readable way of achieving this (not a fan of single line ansible tasks)
- local_action:
module: copy
content: "{{ foo_result }}"
dest: /path/to/destination/file
Source: Stackoverflow.com