[python] How can I get the name of an object in Python?

I ran into this page while wondering the same question.

As others have noted, it's simple enough to just grab the __name__ attribute from a function in order to determine the name of the function. It's marginally trickier with objects that don't have a sane way to determine __name__, i.e. base/primitive objects like basestring instances, ints, longs, etc.

Long story short, you could probably use the inspect module to make an educated guess about which one it is, but you would have to probably know what frame you're working in/traverse down the stack to find the right one. But I'd hate to imagine how much fun this would be trying to deal with eval/exec'ed code.

% python2 whats_my_name_again.py
needle => ''b''
['a', 'b']
[]
needle => '<function foo at 0x289d08ec>'
['c']
['foo']
needle => '<function bar at 0x289d0bfc>'
['f', 'bar']
[]
needle => '<__main__.a_class instance at 0x289d3aac>'
['e', 'd']
[]
needle => '<function bar at 0x289d0bfc>'
['f', 'bar']
[]
%

whats_my_name_again.py:

#!/usr/bin/env python

import inspect

class a_class:
    def __init__(self):
        pass

def foo():
    def bar():
        pass

    a = 'b'
    b = 'b'
    c = foo
    d = a_class()
    e = d
    f = bar

    #print('globals', inspect.stack()[0][0].f_globals)
    #print('locals', inspect.stack()[0][0].f_locals)

    assert(inspect.stack()[0][0].f_globals == globals())
    assert(inspect.stack()[0][0].f_locals == locals())

    in_a_haystack = lambda: value == needle and key != 'needle'

    for needle in (a, foo, bar, d, f, ):
        print("needle => '%r'" % (needle, ))
        print([key for key, value in locals().iteritems() if in_a_haystack()])
        print([key for key, value in globals().iteritems() if in_a_haystack()])


foo()