As I commented you need to use a StringIO object and decode i.e c=pd.read_csv(io.StringIO(s.decode("utf-8"))) if using requests, you need to decode as .content returns bytes if you used .text you would just need to pass s as is s = requests.get(url).text c = pd.read_csv(StringIO(s)).
A simpler approach is to pass the correct url of the raw data directly to read_csv, you don't have to pass a file like object, you can pass a url so you don't need requests at all:
c = pd.read_csv("https://raw.githubusercontent.com/cs109/2014_data/master/countries.csv")
print(c)
Output:
Country Region
0 Algeria AFRICA
1 Angola AFRICA
2 Benin AFRICA
3 Botswana AFRICA
4 Burkina AFRICA
5 Burundi AFRICA
6 Cameroon AFRICA
..................................
From the docs:
filepath_or_buffer :
string or file handle / StringIO The string could be a URL. Valid URL schemes include http, ftp, s3, and file. For file URLs, a host is expected. For instance, a local file could be file ://localhost/path/to/table.csv