if you want to use hex code of color which is in this format #123456 then it is very easily be used, create A variables of type Color and assign the following values to it.
Color myHexColor = Color(0xff123456)
// her you notice I use the 0xff and that is opacity or transparency of the color
// and you can also change these value .
use myhexcolor and you are ready to go .
if you want to change the opacity of color direct from the hex code then change the ff value in 0xff to the respectively value from the table below.
Hex Opacity Values
100% — FF
95% — F2
90% — E6
85% — D9
80% — CC
75% — BF
70% — B3
65% — A6
60% — 99
55% — 8C
50% — 80
45% — 73
40% — 66
35% — 59
30% — 4D
25% — 40
20% — 33
15% — 26
10% — 1A
5% — 0D
0% — 00
The Color
class expects an ARGB integer. Since you try to use it with RGB
value, represent it as int and prefix it with 0xff
.
Color mainColor = Color(0xffb74093);
If you get annoyed by this and still wish to use strings, you can extend Color
and add a string constructor
class HexColor extends Color {
static int _getColorFromHex(String hexColor) {
hexColor = hexColor.toUpperCase().replaceAll("#", "");
if (hexColor.length == 6) {
hexColor = "FF" + hexColor;
}
return int.parse(hexColor, radix: 16);
}
HexColor(final String hexColor) : super(_getColorFromHex(hexColor));
}
usage
Color color1 = HexColor("b74093");
Color color2 = HexColor("#b74093");
Color color3 = HexColor("#88b74093"); // if you wish to use ARGB format
For general reference. There is a simpler way using the library Supercharged. Although, you can use extension methods with all solutions mentioned, you find practical user library toolkit.
"#ff00ff".toColor(); // painless hex to color
"red".toColor(); // supports all web color names
Easier, right?
A simple function without using a class:
Color _colorFromHex(String hexColor) {
final hexCode = hexColor.replaceAll('#', '');
return Color(int.parse('FF$hexCode', radix: 16));
}
You can use it like this:
Color color1 = _colorFromHex("b74093");
Color color2 = _colorFromHex("#b74093");
As the Color constructor does not support hexadecimal string, so we should find other alternatives.
There are several possibilities :
1- The first one is to create a small function that will allow you to convert a color hex-string to a Color object.
Code :
Color colorFromHex(String hexColor) {
final hexCode = hexColor.replaceAll('#', '');
if (hexColor.length == 6) {
hexColor = 'FF' + hexColor; // FF as the opacity value if you don't add it.
}
return Color(int.parse('FF$hexCode', radix: 16));
}
Usage :
Container(
color: colorFromHex('abcdff'),
child: Text(
'Never stop learning',
style: TextStyle(color: colorFromHex('bbffffcc')),
),
)
2- The second possibility is to use the supercharged package. Supercharged brings all the comfort features from languages like Kotlin to all Flutter developers.
Add the dependency supercharged: ^1.X.X
(find recent version) to your project and start using Supercharged everywhere:
import 'package:supercharged/supercharged.dart';
Now ,transform any String to colors
Code :
"#ff00ff".toColor(); // painless hex to color
"red".toColor(); // supports all web color names
You can also use the hexcolor package which is also great .
The most easiest way is to convert it into an integer. For example #bce6eb. You would add 0xff and you would then remove the hashtag making it
0xffbce6eb
Then lets say you were to implement it by doing
backgroundColor: Color(0xffbce6eb)
If you can only use a hexadecimal then I suggest using the Hexcolor package https://pub.dev/packages/hexcolor
String hexString = "45a3df";
Color(int.parse("0xff${hexString}"));
Don't know why this is being downed, this was the solution for me.
Only way that didn't require additional steps
"#b74093"
? OK...
int getColorHexFromStr(String colorStr)
{
colorStr = "FF" + colorStr;
colorStr = colorStr.replaceAll("#", "");
int val = 0;
int len = colorStr.length;
for (int i = 0; i < len; i++) {
int hexDigit = colorStr.codeUnitAt(i);
if (hexDigit >= 48 && hexDigit <= 57) {
val += (hexDigit - 48) * (1 << (4 * (len - 1 - i)));
} else if (hexDigit >= 65 && hexDigit <= 70) {
// A..F
val += (hexDigit - 55) * (1 << (4 * (len - 1 - i)));
} else if (hexDigit >= 97 && hexDigit <= 102) {
// a..f
val += (hexDigit - 87) * (1 << (4 * (len - 1 - i)));
} else {
throw new FormatException("An error occurred when converting a color");
}
}
return val;
}
Use hexcolor for bringing hex colors to dart hexcolorPlugin
hexcolor: ^1.0.4
sample usage
import 'package:hexcolor/hexcolor.dart';
Container(
decoration: new BoxDecoration(
color: Hexcolor('#34cc89'),
),
child: Center(
child: Text(
'Running on: $_platformVersion\n',
style: TextStyle(color: Hexcolor("#f2f2f2")),
),
),
),
To convert from hexadecimal String to int, do :
int hexToInt(String hex)
{
int val = 0;
int len = hex.length;
for (int i = 0; i < len; i++) {
int hexDigit = hex.codeUnitAt(i);
if (hexDigit >= 48 && hexDigit <= 57) {
val += (hexDigit - 48) * (1 << (4 * (len - 1 - i)));
} else if (hexDigit >= 65 && hexDigit <= 70) {
// A..F
val += (hexDigit - 55) * (1 << (4 * (len - 1 - i)));
} else if (hexDigit >= 97 && hexDigit <= 102) {
// a..f
val += (hexDigit - 87) * (1 << (4 * (len - 1 - i)));
} else {
throw new FormatException("Invalid hexadecimal value");
}
}
return val;
}
Call example :
Color color=new Color(hexToInt("FFB74093"));
In Flutter it create a color from RGB with alpha, use
return new Container(
color: new Color.fromRGBO(0, 0, 0, 0.5),
);
How to use hex-color:
return new Container(
color: new Color(0xFF4286f4),
);
//0xFF -> the opacity (FF for opaque)
//4286f4 -> the hex-color
Hex-color with opacity:
return new Container(
color: new Color(0xFF4286f4).withOpacity(0.5),
);
// or change the "FF" value
100% — FF
95% — F2
90% — E6
85% — D9
80% — CC
75% — BF
70% — B3
65% — A6
60% — 99
55% — 8C
50% — 80
45% — 73
40% — 66
35% — 59
30% — 4D
25% — 40
20% — 33
15% — 26
10% — 1A
5% — 0D
0% — 00
For more follow official link https://api.flutter.dev/flutter/dart-ui/Color-class.html
Easy way :
String color = yourHexColor.replaceAll('#', '0xff');
Usage:
Container(
color: Color(int.parse(color)),
)
You can click on Color Widget and it tells you in much deeper information how those letters stand for. You can also use Color.fromARGB() method to create custom colors which is much easier to me. Use Flutter Doctor Color Picker website to pick any color you want for your flutter application.
How to use Hex Color Code #b74093 in Flutter
Simply remove the # sign from hex color code and ad 0xff with color code inside Color class
#b74093
will become Color(0xffb74093)
in Flutter
#B74093
will become Color(0xFFB74093)
in Flutter
the ff or FF
in Color(0xFFB74093)
defines the opacity
I missed the obvious answer using hex numbers for the fromRGB constructor:
Color.fromRGBO(0xb7, 0x40, 0x93, 1),
No need functions
For example to give color to a container using colorcode
Container (
color:Color(0xff000000)
)
Here the 0xff is the format followed by color code
Unfortunately, the Color
class constructor in Flutter does not accept a simple hexadecimal string (like #bfeb91
in CSS).
Instead, it requires an integer like 0xFFBFEB91
.
So here is we convert a hex string to an integer
A simple function
Give this function a hex string and it will return you a Color!
Color _getColorFromHex(String hexColor) {
hexColor = hexColor.replaceAll("#", "");
if (hexColor.length == 6) {
hexColor = "FF" + hexColor;
}
if (hexColor.length == 8) {
return Color(int.parse("0x$hexColor"));
}
}
Use it like this
Text(
'Hello World',
style: TextStyle(backgroundColor: _getColorFromHex('ff00aa')), // or 'bfeb91', or 'ffbfeb91'
),
As a String extension
Leveraging the power of Dart extensions we can augment String
with a function that returns a Color
:
extension ColorExtension on String {
toColor() {
var hexColor = this.replaceAll("#", "");
if (hexColor.length == 6) {
hexColor = "FF" + hexColor;
}
if (hexColor.length == 8) {
return Color(int.parse("0x$hexColor"));
}
}
}
Use it like this
Text(
'Hello World',
style: TextStyle(backgroundColor: '#bfeb91'.toColor()), // or 'bfeb91', or 'ffbfeb91'
),
Thanks for asking this question, simples solution is as:
// Color to Hex String
colorToHexString(Color color) {
return '#FF${color.value.toRadixString(16).substring(2, 8)}';
}
// Hex String to Color
hexStringToColor(String hexColor) {
hexColor = hexColor.toUpperCase().replaceAll("#", "");
if (hexColor.length == 6) {
hexColor = "FF" + hexColor;
}
return Color(int.parse(hexColor, radix: 16));
}
// How to call function
String hexCode = colorToHexString(Colors.green);
Color bgColor = hexStringToColor(hexCode);
print("$hexCode = $bgColor");
Enjoy code and help others :)
If you need Hex color desperately in your application, there is one simple step you can follow:
2. Get your RGB values.
3. In flutter, you have an simple option to use RGB color:
Color.fromRGBO(r_value, g_value, b_value, opacity)
will do the job for you.
4. Go ahead and tweek O_value to get the color you want.
///
/// Convert a color hex-string to a Color object.
///
Color getColorFromHex(String hexColor) {
hexColor = hexColor.toUpperCase().replaceAll('#', '');
if (hexColor.length == 6) {
hexColor = 'FF' + hexColor;
}
return Color(int.parse(hexColor, radix: 16));
}
Text(
'hello world',
style: TextStyle(
color: getColorFromHex('#aabbcc'),
fontWeight: FontWeight.bold,
)
)
Add this function in your file -
Color parseColor(String color) {
String hex = color.replaceAll("#", "");
if (hex.isEmpty) hex = "ffffff";
if (hex.length == 3) {
hex = '${hex.substring(0, 1)}${hex.substring(0, 1)}${hex.substring(1, 2)}${hex.substring(1, 2)}${hex.substring(2, 3)}${hex.substring(2, 3)}';
}
Color col = Color(int.parse(hex, radix: 16)).withOpacity(1.0);
return col;
}
And use it like -
Container(
color: parseColor("#b74093")
)
You can use this
Color getColorFromColorCode(String code){
return Color(int.parse(code.substring(1, 7), radix: 16) + 0xFF000000);
}
There is another solution. If you store your color as normal hex string and don't want to add opacity to it (leading FF): 1) Convert your hex string to int To convert a hex-string to an integer, do one of the following:
var myInt = int.parse(hexString, radix: 16);
or
var myInt = int.parse("0x$hexString");
as a prefix of 0x (or -0x) will make int.parse default to radix of 16.
2) Add opacity to your color via code
Color color = new Color(myInt).withOpacity(1.0);
import 'package:flutter/material.dart';
class HexToColor extends Color{
static _hexToColor(String code) {
return int.parse(code.substring(1, 7), radix: 16) + 0xFF000000;
}
HexToColor(final String code) : super(_hexToColor(code));
}
Import the new class and use it like this HexToColor('#F2A03D')
You can use this package from_css_color to get Color
out of a hex string. It supports both three and six digit RGB hex notation.
Color color = fromCSSColor('#ff00aa')
For optimisation sake create Color instance once for each color and store it somewhere for later usage.
Source: Stackoverflow.com