I would like to make a UILabel clickable.
I have tried this, but it doesn't work:
class DetailViewController: UIViewController {
@IBOutlet weak var tripDetails: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
...
let tap = UITapGestureRecognizer(target: self, action: Selector("tapFunction:"))
tripDetails.addGestureRecognizer(tap)
}
func tapFunction(sender:UITapGestureRecognizer) {
print("tap working")
}
}
This question is related to
ios
swift
uilabel
uitapgesturerecognizer
Have you tried to set isUserInteractionEnabled
to true
on the tripDetails
label? This should work.
Good and convenient solution:
In your ViewController:
@IBOutlet weak var label: LabelButton!
override func viewDidLoad() {
super.viewDidLoad()
self.label.onClick = {
// TODO
}
}
You can place this in your ViewController or in another .swift file(e.g. CustomView.swift):
@IBDesignable class LabelButton: UILabel {
var onClick: () -> Void = {}
override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
onClick()
}
}
In Storyboard select Label and on right pane in "Identity Inspector" in field class select LabelButton.
Don't forget to enable in Label Attribute Inspector "User Interaction Enabled"
SWIFT 4 Update
@IBOutlet weak var tripDetails: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
let tap = UITapGestureRecognizer(target: self, action: #selector(GameViewController.tapFunction))
tripDetails.isUserInteractionEnabled = true
tripDetails.addGestureRecognizer(tap)
}
@objc func tapFunction(sender:UITapGestureRecognizer) {
print("tap working")
}
Swift 5
Similar to @liorco, but need to replace @objc with @IBAction.
class DetailViewController: UIViewController {
@IBOutlet weak var tripDetails: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
...
let tap = UITapGestureRecognizer(target: self, action: #selector(DetailViewController.tapFunction))
tripDetails.isUserInteractionEnabled = true
tripDetails.addGestureRecognizer(tap)
}
@IBAction func tapFunction(sender: UITapGestureRecognizer) {
print("tap working")
}
}
This is working on Xcode 10.2.
Swift 3 Update
Replace
Selector("tapFunction:")
with
#selector(DetailViewController.tapFunction)
Example:
class DetailViewController: UIViewController {
@IBOutlet weak var tripDetails: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
...
let tap = UITapGestureRecognizer(target: self, action: #selector(DetailViewController.tapFunction))
tripDetails.isUserInteractionEnabled = true
tripDetails.addGestureRecognizer(tap)
}
@objc
func tapFunction(sender:UITapGestureRecognizer) {
print("tap working")
}
}
As described in the above solution you should enable the user interaction first and add the tap gesture
this code has been tested using
yourlabel.isUserInteractionEnabled = true
yourlabel.addGestureRecognizer(UITapGestureRecognizer(){
//TODO
})
Pretty easy to overlook like I did, but don't forget to use UITapGestureRecognizer
rather than UIGestureRecognizer
.
For swift 3.0 You can also change gesture long press time duration
label.isUserInteractionEnabled = true
let longPress:UILongPressGestureRecognizer = UILongPressGestureRecognizer.init(target: self, action: #selector(userDragged(gesture:)))
longPress.minimumPressDuration = 0.2
label.addGestureRecognizer(longPress)
You need to enable the user interaction of that label.....
For e.g
yourLabel.userInteractionEnabled = true
Swift 3 Update
yourLabel.isUserInteractionEnabled = true
Source: Stackoverflow.com