How do I find with the LIKE operator in SQL Server

Question

I have a column name Address which consists of some address which has     in between as   Address -------------------- Aman Ja lan  Stree  Ro ad   etc   etc   How I can write the LIKE operator to find that pattern   I tried   declare  var char 1  set  var      select Address from Accomodation where Address like      var

User · Answer

You can use ESCAPE   WHERE columnName LIKE        ESCAPE        SQLFiddle Demo

User · Answer

Try this   declare  var char 3  set  var       select Address from Accomodation where Address like      var        You must use    cancels the effect of wildcard  so you read   as a normal character  idem about character

User · Answer

I would use  WHERE columnName LIKE           SQL Server stores string summary statistics for use in estimating the number of rows that will match a LIKE clause  The cardinality estimates can be better and lead to a more appropriate plan when the square bracket syntax is used   The response to this Connect Item states     We do not have support for precise cardinality estimation in the   presence of user defined escape characters  So we probably get a poor   estimate and a poor plan  We ll consider addressing this issue in a   future release    An example   CREATE TABLE T   X VARCHAR 50   Y CHAR 2000  NULL    CREATE NONCLUSTERED INDEX IX ON T X   INSERT INTO T  X  SELECT TOP  5   10  off  FROM master  spt values UNION ALL SELECT  TOP  100000    blah  FROM master  spt values v1   master  spt values v2   SET STATISTICS IO ON  SELECT   FROM T  WHERE X LIKE          SELECT   FROM T WHERE X LIKE        ESCAPE       Shows 457 logical reads for the first query and 33 335 for the second

[sql-server] How do I find ' % ' with the LIKE operator in SQL Server?

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